Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 24 of 36.
Saurav kumar said:
8 years ago
The cost price-100,
selling price-120.
100 * 20 = 125 * x.
After solving value of x=16.
selling price-120.
100 * 20 = 125 * x.
After solving value of x=16.
Suresh said:
8 years ago
Let C.P. of each article be Re. 2 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
40 - x x 100 = 25.
x
4000 - 100x = 25x,
125x = 4000,
x = 32.
x cannot be equal to 16.
If you presume Rs.1/- as cost price , x becomes 16. If you presume Rs.10/- as cost price, x becomes 160.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
40 - x x 100 = 25.
x
4000 - 100x = 25x,
125x = 4000,
x = 32.
x cannot be equal to 16.
If you presume Rs.1/- as cost price , x becomes 16. If you presume Rs.10/- as cost price, x becomes 160.
RAJA said:
8 years ago
Assume C.p of 20 articles = rs 20 (ie c.p of 1 articles = rs1).
S.p of x articles = c.p of 20 articles,
S.p of x articles = rs 20.
Then c.p of x articles =?.
They told 25% profit.
Profit % =((s.p - c.p)/c.p)*100.
25 = ((20-c.p)/c.p)*100.
C.p of x articles is rs 16.
So, x articles = 16 because c.p of 1 article = rs 1.
S.p of x articles = c.p of 20 articles,
S.p of x articles = rs 20.
Then c.p of x articles =?.
They told 25% profit.
Profit % =((s.p - c.p)/c.p)*100.
25 = ((20-c.p)/c.p)*100.
C.p of x articles is rs 16.
So, x articles = 16 because c.p of 1 article = rs 1.
Vaishnavi said:
8 years ago
Why this (y-x)=(2x-x) is done? Explain.
Milan aryal said:
8 years ago
Bina Chand bought two kettles for Rs 1,625. She sold one of them at 20% profit and the others at 20% loss. If the selling price of both kettles are same, find the total cost price of each kettles and find her gain or loss percent in total transaction.
Can anyone solve this?
Can anyone solve this?
Darakhshan Anjum said:
8 years ago
Well done @Sanjeet.
Kavya said:
8 years ago
Guys, here the key point is that cost price is same as selling price.
Gyanajyoti said:
8 years ago
Hello @Dosto
Let me explain,
In this sum we take Easy method:
Cp=(100/100+GAIN%)s.p.
so
x=(100/125)20
x=16.
Let me explain,
In this sum we take Easy method:
Cp=(100/100+GAIN%)s.p.
so
x=(100/125)20
x=16.
Suman said:
8 years ago
If no of articles are 66 and profit is 22 then what will be the profit %?
Sai reddy said:
8 years ago
As per given question.
CP of 20 articles =SP of x articles.
CP/SP=X/20.
here CP=x, SP=20.
GAIN%=(GAIN/CP) 100.
25 =(20-X/X)100.
X=16.
CP of 20 articles =SP of x articles.
CP/SP=X/20.
here CP=x, SP=20.
GAIN%=(GAIN/CP) 100.
25 =(20-X/X)100.
X=16.
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