Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 25 of 36.
Akash Kalyankar said:
8 years ago
Suppose cost of 1 article is 1 rupees.
The cost of 20 articles is 20 rupees.
1) sp of 20 articles will be 25 (with 25 % profit)
2) what will x be for sp = 20; (as cp 0f 20 = sp )
20 -----> 25.
x ------> 20.
x = 20 * 20 / 25.
x = 16.
The cost of 20 articles is 20 rupees.
1) sp of 20 articles will be 25 (with 25 % profit)
2) what will x be for sp = 20; (as cp 0f 20 = sp )
20 -----> 25.
x ------> 20.
x = 20 * 20 / 25.
x = 16.
Kishore said:
8 years ago
Here ,we dont know the value of s.p but in condition given that , s.p of x articles = 20 articles of c.p.
let c.p of 1 article is 1/-
so,c.p of x article become x/-
as per condition,
s.p of x article is 20/-(s.p of x articles which is equal to c.p of 20 article (i.e 20/-)).
p%=(s.p-c.p)/c.p *100.
=(20-x)/x*100 = 16.
let c.p of 1 article is 1/-
so,c.p of x article become x/-
as per condition,
s.p of x article is 20/-(s.p of x articles which is equal to c.p of 20 article (i.e 20/-)).
p%=(s.p-c.p)/c.p *100.
=(20-x)/x*100 = 16.
Divya Pahwa said:
8 years ago
@Sanjeet Kumar.
Very nice and clear explanation. Thank you.
Very nice and clear explanation. Thank you.
Basil said:
8 years ago
@Rinku.
Best explanation Really simple. Thank you very much.
Best explanation Really simple. Thank you very much.
Mallesh goud said:
8 years ago
(a-b) /b*100=gain percentage.
a=20 b=x gain %=25.
If we solve we get x=16.
a=20 b=x gain %=25.
If we solve we get x=16.
Purusottam said:
8 years ago
As far as my calculation is concerned it is 18.75.
Utsav said:
8 years ago
@Sanjeet.
"profit on one article= (20/x)-'1'
% profit=((20/x)-'1')*100)/1=25"
Why do we have to subtract 1 in the above two steps?
"profit on one article= (20/x)-'1'
% profit=((20/x)-'1')*100)/1=25"
Why do we have to subtract 1 in the above two steps?
Vibhore said:
8 years ago
@Utsav.
Profit = SP - CP.
Therefore Profit = (20/x) - 1.
And Profit % = (Profit/CP)X100.
Therefore Profit % = (((20/x)-1)/1)X100 = 25 %.
Ans x = 16.
Profit = SP - CP.
Therefore Profit = (20/x) - 1.
And Profit % = (Profit/CP)X100.
Therefore Profit % = (((20/x)-1)/1)X100 = 25 %.
Ans x = 16.
Jyothsna said:
8 years ago
@Sowmya your explanation is apt without confusing I just wanna to elaborate some of the formulas.
Jyothsna said:
8 years ago
CP 20 = SP x.
CP/SP=x/20.
=>CP =x; SP =20.
Profit=20-x (Profit=SP-CP).
25 = ((20-x)/x)*100 (P%=P/CP*100).
CP/SP=x/20.
=>CP =x; SP =20.
Profit=20-x (Profit=SP-CP).
25 = ((20-x)/x)*100 (P%=P/CP*100).
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