Aptitude - Profit and Loss - Discussion

Consider CP=100, we know profit 125.
If in 125 rupees - 20 article.
Then in 100 - ?

= 100/125 x 20 = 16.

CP. : SP
100% : 125%
4 : 5

Article 5 : 4 (Inversely proportional).
20 : 16

Answer is 16 article.

Hello, I am confused why profit 25% of cost=20% of the selling price? Explain it.

@Nithi.

Your explain is very nice easy to understand.

Total SP = sp of x item +sp of 20-x items=cp+sp of 20-x items.
Profit = total sp - total c p =cp + sp of 20-x items-cp = sp of 20-x items.
Profit % = profit * 100/cp.
i.e. 25=(20-x) * 100/x.
Therefore, x =16.

Your explanation is awesome @Chetan.

Given

CP of 20 articles = s.p of x articles --> 1.
From formula (s.p=100+p%/100 x c.p).
We get s.p =5/4 c.p --> 2.
Put 2 in 1.
CP of 20 articles = 5/4 c.p of x articles.
CP of 1 article =(5/4 *1/20) c.p of x articles.

Hence we get x = 16.

Let Cost price of each is a & selling price of each is b.
So, 20 * a = b * X.... i.e 20a = bx -------> (i)
Again, as the profit is 25% so,
a * 125/100 = b...... i.e, 5a = 4b -------> (ii)

Dividing Equation (i) by (ii),
20a/5a = bx/4b.
or, 4 = x/4.
or, x = 16. (ans)

(c.p-s.p)/s.p * 100 = per
(20-x)/x * 100 = 25.

Solve it and you get x=16.

Hello everyone,

We can solve as normal way. Such as
Let,
c.p. of 1 article is = y rupees.
S.p. of 1 article is = z rupees.

So c.p. of 20 articles is= 20y rupees,
c.p of x articles is=xy rupees,
s.p. of x articles is= xz rupees,

Given:
c.p of 20 articles=s.p. of x article
20y = xz

So now we apply the % formula (25 % profit is given).

%profit=(profit /c.p. )x 100.
25=[(s.p. of x articles-c.p of x articles)/c.p. of x articles] X 100,
25=[(xz- xy) / xy] X 100 (put xz=20y),
25=[(20y-xy / xy)] X100 = [(20-x)y / xy ] X100=[20-x/x] X 100,
x =16 (Answer).