Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 21 of 36.
Eesan said:
9 years ago
Let the cost price of 1 article = P.
So C.P. of 20 article = 20P.
Now, S.P. of x articles = C.P. of 20 article.
So, S.P. of 1 article = 20P / x.
Profit = S.P - C.P. = 20P/x - P.
Now profit% = ((S.P. - C.P.) * 100)/C.P.
= ((20P / x) - P) * 100/ P = 16.
So C.P. of 20 article = 20P.
Now, S.P. of x articles = C.P. of 20 article.
So, S.P. of 1 article = 20P / x.
Profit = S.P - C.P. = 20P/x - P.
Now profit% = ((S.P. - C.P.) * 100)/C.P.
= ((20P / x) - P) * 100/ P = 16.
Suprotim Paul said:
9 years ago
Good explanation @Sanjeet.
Sreedhar said:
9 years ago
See it's simple.
C.P of 20 article = S.P of X article --> (1)
Let me assume CP of 1 article is 1.
then CP for 20 article it'll be 20.
From condition (1)
CP of 20 article= SP of X article = 20.
Then SP of 1 article = 20/X.
We know that,
Profit %= (SP - CP) * 100/CP.
25 = ((20/X) - 1) * 100).
1/4 = 20 - x/x.
x = 80 - 4X.
5X = 80.
So, x = 16.
C.P of 20 article = S.P of X article --> (1)
Let me assume CP of 1 article is 1.
then CP for 20 article it'll be 20.
From condition (1)
CP of 20 article= SP of X article = 20.
Then SP of 1 article = 20/X.
We know that,
Profit %= (SP - CP) * 100/CP.
25 = ((20/X) - 1) * 100).
1/4 = 20 - x/x.
x = 80 - 4X.
5X = 80.
So, x = 16.
Neha said:
9 years ago
See,
CP of 1 article = 1 Rs,
Similarly CP of 20 articles = 20rs.
SP of x articles = 20 rs.
But 25x profit get on 20 Rs.
So,
125x = 20.
100x = ?
(100 * 20)/125 = 16.
So x = 16.
CP of 1 article = 1 Rs,
Similarly CP of 20 articles = 20rs.
SP of x articles = 20 rs.
But 25x profit get on 20 Rs.
So,
125x = 20.
100x = ?
(100 * 20)/125 = 16.
So x = 16.
SAIRAM said:
9 years ago
Friends it is easy.
20 articles are bought.
Then cost price = 20(A)...i.e A is price of each article so cp = 20A.
And given that X articles are sold at B price, then selling price of X articles are = XB.
And given 20A = XB.
Given 25% profit.
So profit% = profit/cp * 100.
Given total profit so, consider 20 articles.
25 = (20B - 20A)/20A * 100;
100A = 80B
So, A/B = 4/5.
4B = 5A.
Given, 20A = XB.
4 * 5A = XB,
4 * 4B = XB,
16B = XB,
X =16.
20 articles are bought.
Then cost price = 20(A)...i.e A is price of each article so cp = 20A.
And given that X articles are sold at B price, then selling price of X articles are = XB.
And given 20A = XB.
Given 25% profit.
So profit% = profit/cp * 100.
Given total profit so, consider 20 articles.
25 = (20B - 20A)/20A * 100;
100A = 80B
So, A/B = 4/5.
4B = 5A.
Given, 20A = XB.
4 * 5A = XB,
4 * 4B = XB,
16B = XB,
X =16.
Kishan said:
9 years ago
@Neha. Your explaination superb.
Netra said:
9 years ago
What do you mean by Profit is 20% of sales (ie 25% of cost)?
Kumar Prabhat said:
9 years ago
(Goods left/Goods sold) 100 => (20 - X/X) * 100 = 25.
Rocky said:
9 years ago
I can't understand this method. So please solve this by another method.
Nithin said:
9 years ago
Guys, I will tell you a basic logic which I felt.
Assumption but it works
25% of profit.
Means
It can be
Sp - Cp = Profit.
125 - 100 = 25.
So no of items which can be bought is 100/125 = 8.
So, the answer must be a multiple of 8.
Assumption but it works
25% of profit.
Means
It can be
Sp - Cp = Profit.
125 - 100 = 25.
So no of items which can be bought is 100/125 = 8.
So, the answer must be a multiple of 8.
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