Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
360 comments Page 20 of 36.
Rahul said:
1 decade ago
This question is quite simple but the language or the way of asking made in inconvenient to solve. Here is another way to ask the same question.
Cost of an article is 1/20. If you sell it at 25% profit then find out the Selling price?
Cost of an article is 1/20. If you sell it at 25% profit then find out the Selling price?
Abdullah said:
1 decade ago
It's VERY EASY!
Let C.P of 1 article is 1Rs. than C.P of 20 articles is 20 RS.
Again S.P of X articles is 20 RS.
So, S.P of 1 article is 20/x.
Now putting the CP and SP of 1 article and profit% in the standard formula given below.
SP = CP*(100 + GAIN)/100.
We have,
20/x =1*(100 + 25)/100.
20/x = 125/100
2000 = 125x.
x = 16.
Let C.P of 1 article is 1Rs. than C.P of 20 articles is 20 RS.
Again S.P of X articles is 20 RS.
So, S.P of 1 article is 20/x.
Now putting the CP and SP of 1 article and profit% in the standard formula given below.
SP = CP*(100 + GAIN)/100.
We have,
20/x =1*(100 + 25)/100.
20/x = 125/100
2000 = 125x.
x = 16.
Subhajit Mitra said:
1 decade ago
Cost price of m article is equal to selling price of n article then,
Gain or loss% = (m - n/n) *100.
Here,
25 = (20 - x/x)/100.
X = 16.
Gain or loss% = (m - n/n) *100.
Here,
25 = (20 - x/x)/100.
X = 16.
Raunak said:
1 decade ago
@Sanjeet Kumar.
Very well explained and thanks a lot.
Very well explained and thanks a lot.
Rajender Kumar said:
1 decade ago
@Sanjeet could you tell me.
Hence, S. P of x article is Rs. 20.
So S. P. of 1 article = 20/x.
After that, I can't understand why are you using -1 for profit on one article.
Profit on one article= (20/x) - 1.
Please explain me.
Hence, S. P of x article is Rs. 20.
So S. P. of 1 article = 20/x.
After that, I can't understand why are you using -1 for profit on one article.
Profit on one article= (20/x) - 1.
Please explain me.
Manash said:
1 decade ago
Let's assume that the CP of each item is Re 1.
Thus, for 20 items, total CP would be Rs 20.
Given that, he makes a profit of 25%,
ie) He is selling every Re 1 item for Rs. 1.25.
Now, since the CP of 20 items (i.e Rs 20) is equal to the SP of x items, therefore,
x * 1.25 = 20.
=> x= 16.
Thus, for 20 items, total CP would be Rs 20.
Given that, he makes a profit of 25%,
ie) He is selling every Re 1 item for Rs. 1.25.
Now, since the CP of 20 items (i.e Rs 20) is equal to the SP of x items, therefore,
x * 1.25 = 20.
=> x= 16.
Pawar Upendra Dinesh Reddy said:
1 decade ago
@All
Sanjeet Kumar's explanation is clear and understandable.
Sanjeet Kumar's explanation is clear and understandable.
Snist said:
1 decade ago
It should be noted that only x items are to be considered among 20 items during problem-solving.
So, sp of x items = 20 (since given sp of x = cp og 20 ||consider each item is of rs. 1).
And, cp of x items = x (since he bought the x for rs. X. Likewise 20 items for rs. 20).
Profit for selling x items = sp of x - cp of x = 20 - x.
Profit% = (profit/cp) * 100.
= {(20-x)/x} * 100.
So, sp of x items = 20 (since given sp of x = cp og 20 ||consider each item is of rs. 1).
And, cp of x items = x (since he bought the x for rs. X. Likewise 20 items for rs. 20).
Profit for selling x items = sp of x - cp of x = 20 - x.
Profit% = (profit/cp) * 100.
= {(20-x)/x} * 100.
Susanta halder said:
1 decade ago
Thank you sanjeet kumar.
Nat said:
10 years ago
Profit = 25%.
So let c.p = 4 & s.p = 5.
20 * 4 = x * 5 (unknown=x),
16 = x.
So let c.p = 4 & s.p = 5.
20 * 4 = x * 5 (unknown=x),
16 = x.
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