Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 21 of 36.
Darakhshan Anjum said:
8 years ago
Well done @Sanjeet.
Kavya said:
8 years ago
Guys, here the key point is that cost price is same as selling price.
Gyanajyoti said:
8 years ago
Hello @Dosto
Let me explain,
In this sum we take Easy method:
Cp=(100/100+GAIN%)s.p.
so
x=(100/125)20
x=16.
Let me explain,
In this sum we take Easy method:
Cp=(100/100+GAIN%)s.p.
so
x=(100/125)20
x=16.
Suman said:
8 years ago
If no of articles are 66 and profit is 22 then what will be the profit %?
Sai reddy said:
8 years ago
As per given question.
CP of 20 articles =SP of x articles.
CP/SP=X/20.
here CP=x, SP=20.
GAIN%=(GAIN/CP) 100.
25 =(20-X/X)100.
X=16.
CP of 20 articles =SP of x articles.
CP/SP=X/20.
here CP=x, SP=20.
GAIN%=(GAIN/CP) 100.
25 =(20-X/X)100.
X=16.
Akash Kalyankar said:
8 years ago
Suppose cost of 1 article is 1 rupees.
The cost of 20 articles is 20 rupees.
1) sp of 20 articles will be 25 (with 25 % profit)
2) what will x be for sp = 20; (as cp 0f 20 = sp )
20 -----> 25.
x ------> 20.
x = 20 * 20 / 25.
x = 16.
The cost of 20 articles is 20 rupees.
1) sp of 20 articles will be 25 (with 25 % profit)
2) what will x be for sp = 20; (as cp 0f 20 = sp )
20 -----> 25.
x ------> 20.
x = 20 * 20 / 25.
x = 16.
Kishore said:
8 years ago
Here ,we dont know the value of s.p but in condition given that , s.p of x articles = 20 articles of c.p.
let c.p of 1 article is 1/-
so,c.p of x article become x/-
as per condition,
s.p of x article is 20/-(s.p of x articles which is equal to c.p of 20 article (i.e 20/-)).
p%=(s.p-c.p)/c.p *100.
=(20-x)/x*100 = 16.
let c.p of 1 article is 1/-
so,c.p of x article become x/-
as per condition,
s.p of x article is 20/-(s.p of x articles which is equal to c.p of 20 article (i.e 20/-)).
p%=(s.p-c.p)/c.p *100.
=(20-x)/x*100 = 16.
Divya Pahwa said:
8 years ago
@Sanjeet Kumar.
Very nice and clear explanation. Thank you.
Very nice and clear explanation. Thank you.
Basil said:
8 years ago
@Rinku.
Best explanation Really simple. Thank you very much.
Best explanation Really simple. Thank you very much.
Mallesh goud said:
8 years ago
(a-b) /b*100=gain percentage.
a=20 b=x gain %=25.
If we solve we get x=16.
a=20 b=x gain %=25.
If we solve we get x=16.
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