Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
354 comments Page 20 of 36.
Chintu jareda said:
8 years ago
Let, the cost price of one article is = C.P.
Then cost price of 20 article is = 20 * C.P.
And cost price of x article will be =x * C.P.
Given that % profit is 25%.i.e.,prifit = 25% of C.P.
Now we know that, selling price=cost price+profit = 1.25 * C.P.
Hence, selling price of x articles = x * (1.25 * C.P).
Given that s.p. of x article =c.p. of 20article.
x * (1.25 * C.P.) = 20 * C.P.
x = 20/1.25 = 16 Ans.
Then cost price of 20 article is = 20 * C.P.
And cost price of x article will be =x * C.P.
Given that % profit is 25%.i.e.,prifit = 25% of C.P.
Now we know that, selling price=cost price+profit = 1.25 * C.P.
Hence, selling price of x articles = x * (1.25 * C.P).
Given that s.p. of x article =c.p. of 20article.
x * (1.25 * C.P.) = 20 * C.P.
x = 20/1.25 = 16 Ans.
Suman Sourav said:
8 years ago
If I bought 20 article and sell 16 article that means 4 article saved, gain 25% (125=20 equ i and 100= x.....Equ 2 ) req article 16 will get easily.
Usha said:
8 years ago
Ans: d.
By using the formula.
Sp=(100+gain%)*cp/100.
Here cp of 20 articles = sp of x articles.
So,
Cp of 1 article = sp of x/20 articles.
X/20=(100+25)*1/100,
=>x=25.
By using the formula.
Sp=(100+gain%)*cp/100.
Here cp of 20 articles = sp of x articles.
So,
Cp of 1 article = sp of x/20 articles.
X/20=(100+25)*1/100,
=>x=25.
Vff said:
8 years ago
why we assume cp =1?
Can anybody explain it?
Can anybody explain it?
Saurav kumar said:
8 years ago
The cost price-100,
selling price-120.
100 * 20 = 125 * x.
After solving value of x=16.
selling price-120.
100 * 20 = 125 * x.
After solving value of x=16.
Aravind said:
8 years ago
Can't understand. Please explain me.
Suresh said:
8 years ago
Let C.P. of each article be Re. 2 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
40 - x x 100 = 25.
x
4000 - 100x = 25x,
125x = 4000,
x = 32.
x cannot be equal to 16.
If you presume Rs.1/- as cost price , x becomes 16. If you presume Rs.10/- as cost price, x becomes 160.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
40 - x x 100 = 25.
x
4000 - 100x = 25x,
125x = 4000,
x = 32.
x cannot be equal to 16.
If you presume Rs.1/- as cost price , x becomes 16. If you presume Rs.10/- as cost price, x becomes 160.
RAJA said:
8 years ago
Assume C.p of 20 articles = rs 20 (ie c.p of 1 articles = rs1).
S.p of x articles = c.p of 20 articles,
S.p of x articles = rs 20.
Then c.p of x articles =?.
They told 25% profit.
Profit % =((s.p - c.p)/c.p)*100.
25 = ((20-c.p)/c.p)*100.
C.p of x articles is rs 16.
So, x articles = 16 because c.p of 1 article = rs 1.
S.p of x articles = c.p of 20 articles,
S.p of x articles = rs 20.
Then c.p of x articles =?.
They told 25% profit.
Profit % =((s.p - c.p)/c.p)*100.
25 = ((20-c.p)/c.p)*100.
C.p of x articles is rs 16.
So, x articles = 16 because c.p of 1 article = rs 1.
Vaishnavi said:
8 years ago
Why this (y-x)=(2x-x) is done? Explain.
Milan aryal said:
8 years ago
Bina Chand bought two kettles for Rs 1,625. She sold one of them at 20% profit and the others at 20% loss. If the selling price of both kettles are same, find the total cost price of each kettles and find her gain or loss percent in total transaction.
Can anyone solve this?
Can anyone solve this?
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