Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 9 of 11.
Prateek said:
1 decade ago
What is the time taken for faster train to cross the slower train?
Rony said:
5 years ago
Why not solve in km?
Speed & distance should be in km, right?
Speed & distance should be in km, right?
Ram said:
7 years ago
Guys, can anyone explain how 41.6666667 was turn into 125/3?
Ram said:
1 decade ago
Please explain the step 150*5/18=3/125 how it will came ?
Jyothi said:
10 years ago
km/hr = 1000 m/3600 sec = 5/18 m/sec [1000/3600 = 5/18].
CHANDRU said:
1 decade ago
Train moving in opposite direction why are you adding?
Divyan said:
1 decade ago
Why we are not simplifying 125/3? Please help me guys.
Shri said:
3 years ago
Yes, absolutely right Agree with you @Hadiyal Jignesh.
(3)
Gou said:
6 years ago
How to solve (2000*3÷125) ? please explain in breif.
Jinni said:
5 years ago
The time for the long train will be the same right?
(2)
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