Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 1 of 11.
Subhash said:
3 days ago
T = D/S.
D = 1100m + 900m = 2,000.
S(relative) = (60+90) * 5/18 = 41.667,
T = 2000/41.667 =48.
D = 1100m + 900m = 2,000.
S(relative) = (60+90) * 5/18 = 41.667,
T = 2000/41.667 =48.
Nanda said:
1 month ago
Please explain the answer.
God Here said:
6 months ago
@All.
Here's the solution:
Total distance = 2km;
total speed = 150;
time in seconds = (2/150)x3600 = 48 Answer.
Here's the solution:
Total distance = 2km;
total speed = 150;
time in seconds = (2/150)x3600 = 48 Answer.
(8)
Tanmoy Pramanick said:
2 years ago
The right answer will be 28.8 sec.
(6)
Kaviprema said:
2 years ago
Soluution,
First, the direction of the train is opposite so we will add the speed s1+s2..
Then, the length of the train first and second train t1+t2..
S1 + S2=60 + 90 = 150 km/hr.
T1+T2 = 1.10 + 0.9 = 2 km.
Formula,
t= d/s
t = 2km/150km/hr
1km-1000m
So, 2km - 2000m.
t = 2000m/150 *5/18 m/sec.
Convert km/hr into m/sec;
(150 km/hr -> 5/18 m/sec).
After solving we will get,
t= 48sec.
First, the direction of the train is opposite so we will add the speed s1+s2..
Then, the length of the train first and second train t1+t2..
S1 + S2=60 + 90 = 150 km/hr.
T1+T2 = 1.10 + 0.9 = 2 km.
Formula,
t= d/s
t = 2km/150km/hr
1km-1000m
So, 2km - 2000m.
t = 2000m/150 *5/18 m/sec.
Convert km/hr into m/sec;
(150 km/hr -> 5/18 m/sec).
After solving we will get,
t= 48sec.
(18)
Shri said:
3 years ago
Yes, absolutely right Agree with you @Hadiyal Jignesh.
(3)
Sam said:
3 years ago
It is confusing for getting it. Anyone, please explain me to get this.
(4)
Datta vadare said:
4 years ago
T = length/speed.
T = 2000/3/725,
T = 48 sec.
T = 2000/3/725,
T = 48 sec.
(7)
Jakath said:
4 years ago
U = (1.10+0.9)km/(90+60)km/hr,
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
(8)
Jakath said:
4 years ago
U = (1.10+0.9)km/(90+60)km/hr,
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
(4)
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