Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
111 comments Page 2 of 12.
Sam said:
5 years ago
It is confusing for getting it. Anyone, please explain me to get this.
(5)
Datta vadare said:
5 years ago
T = length/speed.
T = 2000/3/725,
T = 48 sec.
T = 2000/3/725,
T = 48 sec.
(7)
Jakath said:
5 years ago
U = (1.10+0.9)km/(90+60)km/hr,
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
(8)
Jakath said:
5 years ago
U = (1.10+0.9)km/(90+60)km/hr,
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
(4)
Shubham said:
6 years ago
@All.
No matter about the slow or fast train, it's only a confusing statement, as no matter what speed is, both trains will cross each other at the same time.
No matter about the slow or fast train, it's only a confusing statement, as no matter what speed is, both trains will cross each other at the same time.
(37)
Sathya said:
6 years ago
If the faster train is cross across the slow train?
Then, What is the answer?
Then, What is the answer?
(6)
Jinni said:
6 years ago
The time for the long train will be the same right?
(2)
Rony said:
6 years ago
Why not solve in km?
Speed & distance should be in km, right?
Speed & distance should be in km, right?
Madhav Kulkarni said:
7 years ago
Relative Speed in Opposite Direction = 60+50 = 150km/h=150*(5/18)=41.66.
Train Length = 1.10+0.9=2Km=2000.
Time=Distance/Speed=2000/41.66=48.
So, the Answer is 48.
Train Length = 1.10+0.9=2Km=2000.
Time=Distance/Speed=2000/41.66=48.
So, the Answer is 48.
(2)
Gou said:
7 years ago
How to solve (2000*3÷125) ? please explain in breif.
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