Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
= | ![]() |
150 x | 5 | ![]() |
18 |
= | ![]() |
125 | ![]() |
3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = | ![]() |
2000 x | 3 | ![]() |
125 |
Discussion:
107 comments Page 2 of 11.
Shubham said:
4 years ago
@All.
No matter about the slow or fast train, it's only a confusing statement, as no matter what speed is, both trains will cross each other at the same time.
No matter about the slow or fast train, it's only a confusing statement, as no matter what speed is, both trains will cross each other at the same time.
(36)
Sathya said:
5 years ago
If the faster train is cross across the slow train?
Then, What is the answer?
Then, What is the answer?
(6)
Jinni said:
5 years ago
The time for the long train will be the same right?
(2)
Rony said:
5 years ago
Why not solve in km?
Speed & distance should be in km, right?
Speed & distance should be in km, right?
Madhav Kulkarni said:
6 years ago
Relative Speed in Opposite Direction = 60+50 = 150km/h=150*(5/18)=41.66.
Train Length = 1.10+0.9=2Km=2000.
Time=Distance/Speed=2000/41.66=48.
So, the Answer is 48.
Train Length = 1.10+0.9=2Km=2000.
Time=Distance/Speed=2000/41.66=48.
So, the Answer is 48.
(2)
Gou said:
6 years ago
How to solve (2000*3÷125) ? please explain in breif.
Crack said:
6 years ago
I know why 5/18 is calculate. But in this particular math they didn't mention anything related to meter. Only answer is given in second, so we should only convert hr to seconds right? why we converted the km also? train length and speed both are in km, also in answer there's no km unit, only second. So please explain this part.
Srinivas said:
6 years ago
Simply, the solution is;
2 km =2000.
=150 * 5/18 is 41.66.
So 2000/41.66 = 48.
2 km =2000.
=150 * 5/18 is 41.66.
So 2000/41.66 = 48.
Hsu Hsu said:
6 years ago
Why do you sum the relation speed of the train in the opposite direction?
If direction are same, will you sum?
Please, someone, explain to me, I need help!
If direction are same, will you sum?
Please, someone, explain to me, I need help!
Shalinwilson said:
7 years ago
No need to convert to m/s.
Because everything in m and h.
Simply relative speed = 60+90 = 150 km/h.
Distance = 1.1+9 = 2 km.
2/150 = .013 hr (in seconds its .013*60 *60 = 48 seconds.
Because everything in m and h.
Simply relative speed = 60+90 = 150 km/h.
Distance = 1.1+9 = 2 km.
2/150 = .013 hr (in seconds its .013*60 *60 = 48 seconds.
(2)
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