Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = | ![]() |
150 x | 5 | m/sec |
| 18 |
| = | ![]() |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | ![]() |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
111 comments Page 12 of 12.
Mohd. Nafees said:
2 decades ago
Hi, can you pleas explain me that why you multiply 2000 with 3/125. Why it is not multiply by 125/3?
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers

m/sec