Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 11 of 11.
Pavan said:
1 decade ago
Hi arun great job.
Arun said:
1 decade ago
@jyoti :90>60 so train wit speed 60 s d slower train.. V need not calculate d speed of d faster train.. It can be done using d formula a+b/u+v... Where a is d distance trav by faster train and b s dat of slower..u and v r d speeds of faster and slower trains
Jyoti said:
1 decade ago
How can you know it is the speed of the slower train?how the time taken by the faster train be calculated?
Deepti said:
1 decade ago
In opposite direction speed are summed up and in same direction speed are subtracted.
CHANDRU said:
1 decade ago
Train moving in opposite direction why are you adding?
Nandy said:
2 decades ago
Time=length/speed
required time=(2000/(125/3))
which is equal to=2000*(3/125)
required time=(2000/(125/3))
which is equal to=2000*(3/125)
Mohd. Nafees said:
2 decades ago
Hi, can you pleas explain me that why you multiply 2000 with 3/125. Why it is not multiply by 125/3?
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers