Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 10 of 11.
Himanshu said:
1 decade ago
If the question be:
The time taken by the faster train to cross the slower train in seconds is. ?
What would be the working and answer?
The time taken by the faster train to cross the slower train in seconds is. ?
What would be the working and answer?
Himanshu said:
1 decade ago
Is there be any need to convert the speed and distance into mtrs? We could have been done it without converting to mtrs i.e. in kms only.
Sundar said:
1 decade ago
@Sathish
1 km = 1000 m
2 km = 1000 x 2 = 2000m.
1 km = 1000 m
2 km = 1000 x 2 = 2000m.
Sathish said:
1 decade ago
How to change 2km = 2000m ?
Hadiyal Jignesh said:
1 decade ago
Kiran There is no subtraction in formula we are adding the 1.10 km + 0.9 km = 2 km
right?
right?
Kiran said:
1 decade ago
But can you tell me when we subtract (1.10km-0.9km)it becomes(0.2km)
then how can it becomes 2 km. Please explain.
then how can it becomes 2 km. Please explain.
Anjan said:
1 decade ago
Hi frds. Well I have a doubt. How can a slower train ever cross the faster one?.
Arulmozhi said:
1 decade ago
When the two trains moving towards or in opposite direction that time we find relative speed.
Am I correct?.
Am I correct?.
Ambika said:
1 decade ago
When & why we find relative speed. Plz explain to me I forget
Raj said:
1 decade ago
Use simple formula :
1)if 2 things acts in same direction( may be 2 trains or train&jogger)
time they meet t=(x+y)/(u-v)
where x,y-distance of trains or something
u,v-speed's in mps.
2)if 2 things acts in opposite direction:
time they meet t=(x+y)/(u+v)
1)if 2 things acts in same direction( may be 2 trains or train&jogger)
time they meet t=(x+y)/(u-v)
where x,y-distance of trains or something
u,v-speed's in mps.
2)if 2 things acts in opposite direction:
time they meet t=(x+y)/(u+v)
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