Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
36
45
48
49
Answer: Option
Explanation:

Relative speed = (60+ 90) km/hr

   = 150 x 5 m/sec
18

   = 125 m/sec.
3

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time = 2000 x 3 sec = 48 sec.
125

Discussion:
107 comments Page 1 of 11.

Mohd. Nafees said:   2 decades ago
Hi, can you pleas explain me that why you multiply 2000 with 3/125. Why it is not multiply by 125/3?
(1)

Nandy said:   2 decades ago
Time=length/speed
required time=(2000/(125/3))
which is equal to=2000*(3/125)

CHANDRU said:   1 decade ago
Train moving in opposite direction why are you adding?

Deepti said:   1 decade ago
In opposite direction speed are summed up and in same direction speed are subtracted.

Jyoti said:   1 decade ago
How can you know it is the speed of the slower train?how the time taken by the faster train be calculated?

Arun said:   1 decade ago
@jyoti :90>60 so train wit speed 60 s d slower train.. V need not calculate d speed of d faster train.. It can be done using d formula a+b/u+v... Where a is d distance trav by faster train and b s dat of slower..u and v r d speeds of faster and slower trains

Pavan said:   1 decade ago
Hi arun great job.

Raj said:   1 decade ago
Use simple formula :
1)if 2 things acts in same direction( may be 2 trains or train&jogger)
time they meet t=(x+y)/(u-v)
where x,y-distance of trains or something
u,v-speed's in mps.
2)if 2 things acts in opposite direction:
time they meet t=(x+y)/(u+v)

Ambika said:   1 decade ago
When & why we find relative speed. Plz explain to me I forget

Arulmozhi said:   1 decade ago
When the two trains moving towards or in opposite direction that time we find relative speed.

Am I correct?.


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