Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 8 of 11.
Sathya said:
5 years ago
If the faster train is cross across the slow train?
Then, What is the answer?
Then, What is the answer?
(6)
Nandy said:
2 decades ago
Time=length/speed
required time=(2000/(125/3))
which is equal to=2000*(3/125)
required time=(2000/(125/3))
which is equal to=2000*(3/125)
Geenee said:
10 years ago
Why km is converted into meter though there all information is in kilometer?
Murali said:
9 years ago
T = D/S.
T = 2km/150km/hr.
Is this is right?
Please, Tell me how to solve.
T = 2km/150km/hr.
Is this is right?
Please, Tell me how to solve.
Ajit vishwakarma said:
1 decade ago
What do you mine time taken by the slower train to cross the faster train?
Sainath said:
8 years ago
Then, What will be the time taken by faster train to cross slower train?
Sam said:
3 years ago
It is confusing for getting it. Anyone, please explain me to get this.
(4)
Vijay said:
1 decade ago
Why we want to multiply it by 3/125 instead of multiplying by 125/3?
Tarek said:
7 years ago
Then the time taken by the faster train to cross the slower will be?
(1)
Ambika said:
1 decade ago
When & why we find relative speed. Plz explain to me I forget
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