Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 7 of 11.
Hadiyal Jignesh said:
1 decade ago
Kiran There is no subtraction in formula we are adding the 1.10 km + 0.9 km = 2 km
right?
right?
Gowtham said:
1 decade ago
How can add 1.10+.9 the train moves opposite direction so subract only pls clear my doubt
Vaasudevarao said:
1 decade ago
Formula (a+b)/(x+y) =1.10+.90/60+90
=2km/150km/h
=2000m/150*5/18
=2000*3/125
=48 sec
=2km/150km/h
=2000m/150*5/18
=2000*3/125
=48 sec
Surojitsaha said:
1 decade ago
So, you mean time taken by the faster train is also same as time taken by slower train.
Sonu kumar said:
1 decade ago
When two train moving in opposite direction then how it possible they cross each other?
Suriya mohan said:
9 years ago
When two trains travel in parallel, then the time of train must be subtracted or added?
Deepti said:
1 decade ago
In opposite direction speed are summed up and in same direction speed are subtracted.
Bismillah khan said:
1 decade ago
No need to convert Km to m, conversion is due to hr to sec because answer is in sec.
Anjan said:
1 decade ago
Hi frds. Well I have a doubt. How can a slower train ever cross the faster one?.
Srinivas said:
6 years ago
Simply, the solution is;
2 km =2000.
=150 * 5/18 is 41.66.
So 2000/41.66 = 48.
2 km =2000.
=150 * 5/18 is 41.66.
So 2000/41.66 = 48.
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