Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 6 of 11.
Amul said:
1 decade ago
Wow super explanation. Im workouting by doing these derivations. All usefull problems with formulas. Thanks.
Jyoti said:
1 decade ago
How can you know it is the speed of the slower train?how the time taken by the faster train be calculated?
Ragi said:
1 decade ago
For what purpose we are converting the kilometer into meter? can't we solve this problem with length 2km.
Jakath said:
4 years ago
U = (1.10+0.9)km/(90+60)km/hr,
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
(8)
Jakath said:
4 years ago
U = (1.10+0.9)km/(90+60)km/hr,
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
(4)
Maurya vinay lucknow said:
1 decade ago
T = D/S .
D = 2 KM = 2000M.
S = 150KM/HR = 150X5/18 = 125/3.
T = 2000/[125/3] = 2000X3/125 = 48 sec.
D = 2 KM = 2000M.
S = 150KM/HR = 150X5/18 = 125/3.
T = 2000/[125/3] = 2000X3/125 = 48 sec.
Mohd. Nafees said:
2 decades ago
Hi, can you pleas explain me that why you multiply 2000 with 3/125. Why it is not multiply by 125/3?
(1)
Amrutha said:
1 decade ago
In the above given that:
T = x+y/u+v for opposite direction.
Can you please apply in this problem?
T = x+y/u+v for opposite direction.
Can you please apply in this problem?
Adm said:
10 years ago
But here don't we need to consider length of longer train only because faster will cross beforehand.
Subhash said:
1 week ago
T = D/S.
D = 1100m + 900m = 2,000.
S(relative) = (60+90) * 5/18 = 41.667,
T = 2000/41.667 =48.
D = 1100m + 900m = 2,000.
S(relative) = (60+90) * 5/18 = 41.667,
T = 2000/41.667 =48.
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