Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
= | ![]() |
150 x | 5 | ![]() |
18 |
= | ![]() |
125 | ![]() |
3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = | ![]() |
2000 x | 3 | ![]() |
125 |
Discussion:
107 comments Page 11 of 11.
Aarti said:
1 decade ago
Why are you multiplying 150*5/8?
Sathish said:
1 decade ago
How to change 2km = 2000m ?
Nanda said:
1 month ago
Please explain the answer.
Agasthya Rana said:
1 decade ago
Why are we adding speed?
Pavan said:
1 decade ago
Hi arun great job.
Karthik said:
9 years ago
How to get 125/3?
Anand said:
1 decade ago
Why 5/18?
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