Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 10 of 11.
Sundar said:
1 decade ago
@Sathish
1 km = 1000 m
2 km = 1000 x 2 = 2000m.
1 km = 1000 m
2 km = 1000 x 2 = 2000m.
Harsh said:
1 decade ago
If both of them are in km then why convert in m. ?
Sara said:
1 decade ago
Please explain this
(1.10+0.9)/(60+90)*5/18
=48
(1.10+0.9)/(60+90)*5/18
=48
Datta vadare said:
4 years ago
T = length/speed.
T = 2000/3/725,
T = 48 sec.
T = 2000/3/725,
T = 48 sec.
(7)
Ramya said:
1 decade ago
How 5/18 came? Can you please explain me?
Virat said:
1 decade ago
Please explain me how can we find 125/3?
Santhu said:
10 years ago
Km/hr convert meter/sec=5/18 multiple.
Sriram said:
8 years ago
How you take covered distance as 2km?
Surya said:
9 years ago
2km/150km/hr * 3600.
Answer 48sec.
Answer 48sec.
Tanmoy Pramanick said:
2 years ago
The right answer will be 28.8 sec.
(6)
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