Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 15)
15.
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer: Option
Explanation:
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
| = |  |
66 x | 5 |  m/sec |
| 18 |
| = | |
55 | m/sec. |
| 3 |
 Time taken to pass the man = |
|
110 x | 3 | sec = 6 sec. |
| 55 |
Discussion:
35 comments Page 3 of 4.
Rahul raj said:
9 years ago
Because train are moving across the man.
The man is not considered as pole so only train distance is total distance.
The man is not considered as pole so only train distance is total distance.
Sarang said:
7 years ago
Distance =speed *time.
110m=60+6km/h*time,
110=66*5/18*time,
110=66*.27*time,
110=17.8 or 18 *time,
Time=110/18=6 s.
110m=60+6km/h*time,
110=66*5/18*time,
110=66*.27*time,
110=17.8 or 18 *time,
Time=110/18=6 s.
(5)
Shanmu said:
1 decade ago
1 km=1000m
1 hour=3600 seconds
to convert from km/hour into m/sec
1000/3600=5/18 m/sec
got it !
1 hour=3600 seconds
to convert from km/hour into m/sec
1000/3600=5/18 m/sec
got it !
Arun said:
1 decade ago
hi.. can anyone just tell me why we r 55/3 as reciprocal to 3/55........? reply if u know....
Shashi said:
1 decade ago
Hai friends please can you provide some formulas which are related to these problems.
Buvana said:
1 decade ago
Please any one give the reason for not considering distance covered by man.
Buvana said:
1 decade ago
Please any one give the reason for not considering distance covered by man.
Pritam said:
8 years ago
Guys, we have to subtract the distance of the man i.e distance from 110.
(1)
Tarun said:
2 decades ago
Hey ramesh,
If you know the derivation please let us know.
If you know the derivation please let us know.
(1)
Samir said:
9 years ago
66 * 5/18,
So
66/6 =11,
18/6 = 3,
11* 5 = 55.
Hence 55/3.
So
66/6 =11,
18/6 = 3,
11* 5 = 55.
Hence 55/3.
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