Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 15)
15.
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer: Option
Explanation:
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
= | ![]() |
66 x | 5 | ![]() |
18 |
= | ![]() |
55 | ![]() |
3 |
![]() |
![]() |
110 x | 3 | ![]() |
55 |
Discussion:
35 comments Page 4 of 4.
Sunil said:
6 years ago
Hi, I don't know how it is calculated.
(66*5/18) = 55/3.
(66*5/18) = 55/3.
(2)
Priya said:
9 years ago
Hi.
How is possible to come 55/3?
Please advice me.
How is possible to come 55/3?
Please advice me.
(1)
Chellem said:
1 decade ago
How it comes 5/18? anyone please reply.
Vamshi said:
7 years ago
@Arun.
110/x = 55/3.
X = 110 * 3/55.
110/x = 55/3.
X = 110 * 3/55.
(1)
Sarah said:
1 decade ago
@mini:
Nice explanation friend.
Nice explanation friend.
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