Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Answer: Option
Explanation:
23) 1056 (45
92
---
136
115
---
21
---
Required number = (23 - 21)
= 2.
Discussion:
73 comments Page 7 of 8.
@ammu said:
9 years ago
Thank you friends. Now it's easy to understand.
Amit said:
9 years ago
Nice trick @Sankar.
Gayatri said:
9 years ago
Nikitha has explained well that everyone can understand easily.
Thank you @Nikitha.
Thank you @Nikitha.
Lavanya Sankari said:
10 years ago
I can understand it very clearly.
Bhupendra said:
10 years ago
23^2 = 529.
And 529x2 = 1058.
Given 1056, difference = 2.
And 529x2 = 1058.
Given 1056, difference = 2.
Raghavi said:
9 years ago
@Sankar & @Prashant.
Is the digital root method is applicable for all the divisors?
Is the digital root method is applicable for all the divisors?
Abhijit Mukherjee said:
1 decade ago
@Nikitha please explain it.
But if we divide 1056 by 23, the remainder is 2.
So if 2 is added to the 1056, we get remainder 0.
Therefore solution is 2.
But if we divide 1056 by 23, the remainder is 2.
So if 2 is added to the 1056, we get remainder 0.
Therefore solution is 2.
HMT said:
1 decade ago
If we do 1056/23. Then remainder = 21.
= 23-21 = 2.
Because to make 23 we have to add 2 in remainder. So we can do 23/23 which is 0.
= 23-21 = 2.
Because to make 23 we have to add 2 in remainder. So we can do 23/23 which is 0.
Prashant said:
1 decade ago
Digital sum method works here:
1056+2 = 1058--- 5 (digital sum).
1056+18 = 1074---3.
1056+3 = 1059-- 6.
1077+21 = 1098--9.
And the digital sum of 23 is 5. So option (A) is correct.
1056+2 = 1058--- 5 (digital sum).
1056+18 = 1074---3.
1056+3 = 1059-- 6.
1077+21 = 1098--9.
And the digital sum of 23 is 5. So option (A) is correct.
Rocky said:
1 decade ago
23*46 = 1058.
Therefore if we add 2 to 1056 then it is divisible by 23.
Therefore if we add 2 to 1056 then it is divisible by 23.
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