Aptitude - Numbers - Discussion

@Nikitha please explain it.

But if we divide 1056 by 23, the remainder is 2.

So if 2 is added to the 1056, we get remainder 0.

Therefore solution is 2.

If we do 1056/23. Then remainder = 21.

= 23-21 = 2.

Because to make 23 we have to add 2 in remainder. So we can do 23/23 which is 0.

Digital sum method works here:

1056+2 = 1058--- 5 (digital sum).

1056+18 = 1074---3.

1056+3 = 1059-- 6.

1077+21 = 1098--9.

And the digital sum of 23 is 5. So option (A) is correct.

23*46 = 1058.

Therefore if we add 2 to 1056 then it is divisible by 23.

Consider the number 13. When we divide it by 6, the remainder is 1. Now, what must be added to 13 to make it completely divisible by 6?

12 is completely divisible by 6. We must add 6 more to 12 to make it divisible by 6. While dividing by 13, the remainder is 1. So we add 5 (6-1) more to make the number 13 divisible by 6.

Similarly in this case, we add 2 (23-21).

Consider first 3 digits 105.
23*4=92; 105-92=13.

Now 13 & remaining digit 6 forms 136.
23*5=115; 136-115=21.

If we are adding 2 in 21 then it will completely divisible.