Aptitude - Numbers - Discussion

First divide 1056 by 23.
Remainder = 21
If we want 1056 totally divisible by 23 so we must add 2 to remainder 21 to make it 23.
Now the remainder is zero.
So, the correct answer is 2.

What least number should be added to 94 so that the sum is completely divisible by 4?

Can anyone answer this?

Let's make it simpler,

23*23 = 529.

To get a number closer to 1056.

529*2 = 1058.

What do we need to add to 1056 to make 1058?
1058-1056 = 2.

Since,
23 * 46 = 1058.
And the given number is 1056,
1058 - 1056 = 2 is the answer.

1056/23.

The simple method is;
The digit sum of 1056 = 12 = 3,
The digit sum of 23 = 5.

So what must be added to 3 to be divisible by 5 i.e 2 is the correct answer.

@All.

The solution is

Adding the first option 2 with 1054 then we get 1056 when it is divided by 23 it gives the perfect number 46.

Doing this same procedure for all the options we get the answer in point. So, the first option is correct.

Whenever we divide any no then we want to break that no in such a group that each group contains equal no of elements.

For eg: If I divide 20/10 means I want to divide 20 in such groups that each group contains 10 elements here we get 2 is a no of groups that is our quotient. 20 is totally divided by 10 hence remainder is zero. In the above example (1056/23) also we have to break 1056 in groups of 23 elements. After division, it gives the remainder of 21 and quotient is 45. It is clear that if I add 2 more elements in a group of 21 then only I will get the 46th group of 23 elements and also get the no which is fully divided by 23.

So, 1056 + 2 = 1058 and 1058/23 gives quotient 46 and remainder as 0.

Got the answer now. Thanks, everyone for the explanation.

The best way lets assume 1056 to be 1+0+5+6=12=1+2=3 --> 1.
23=2+3=5 --> 2.

Hence 2 must be added to (1) to get completely divisible by 23.

How can 1056-92 be 136?

It comes 964.