Aptitude - Numbers - Discussion

Whenever we divide any no then we want to break that no in such a group that each group contains equal no of elements.

For eg: If I divide 20/10 means I want to divide 20 in such groups that each group contains 10 elements here we get 2 is a no of groups that is our quotient. 20 is totally divided by 10 hence remainder is zero. In the above example (1056/23) also we have to break 1056 in groups of 23 elements. After division, it gives the remainder of 21 and quotient is 45. It is clear that if I add 2 more elements in a group of 21 then only I will get the 46th group of 23 elements and also get the no which is fully divided by 23.

So, 1056 + 2 = 1058 and 1058/23 gives quotient 46 and remainder as 0.

Consider the number 13. When we divide it by 6, the remainder is 1. Now, what must be added to 13 to make it completely divisible by 6?

12 is completely divisible by 6. We must add 6 more to 12 to make it divisible by 6. While dividing by 13, the remainder is 1. So we add 5 (6-1) more to make the number 13 divisible by 6.

Similarly in this case, we add 2 (23-21).

Simple,

They are asking only which is a least number make 1056 becomes divisible by 23.
So, we know divisibility means the remainder will be zero.

First, divide the1056 by 23.

And; we know 23*6=138, hence the given number 105(6) is must be 105(8) then we divided). Hence add 2 finally we get remainder zero.

Hi dude.

We have 4 choices in question paper.

Firs to add 1056+2 = 1058, 1058/23 = 0, we got no remaining in finally.

1056+3 = 1059, 1059/23 = 1 we gotta remaining.

1056+18 = 1074, 1074/23 = 16, same like got remaining.

Finally 1056+21 = 1077, 1077/23 = 19, same like got remaining.

Ans = 2.

1056/23.

=23/1056/46
92
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136
138
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When we multiply 23*5=115.
2
But I take one 1 more bigger digit I multiply 23*6=138
Difference of this two numbers is 2.
This is the simplest way.

To find the correct no to add in amt 1056 it is divided by 23 to like 23*4 = 92 & its minus from 1056 then it remains 136 then its divided by 23*5 = 115 & minus from 136 then the remaining amt is 21 so there must be add 2 no.(21+2=23) so the ramaining amt will be zero.

@All.

The solution is

Adding the first option 2 with 1054 then we get 1056 when it is divided by 23 it gives the perfect number 46.

Doing this same procedure for all the options we get the answer in point. So, the first option is correct.

It is so easy..

If the number 1056 is completely divisible by 23 means, remainder should come zero..

But if we divide 1056 by 23, the remainder is 2..

So if 2 is added to the 1056, we get remainder 0.

Therefore solution is 2

Find digital root for 1056. 1+5+6=12, 1+2= 3 digital root should be less than or equal to one. Digital root for 23 is 2+3=5 so it will of form 3/5 for to exactly divisible we need to add 2 to numerator so answer is 2.

When 1056 divided by 23 it yields 21 but we need to get "0" as remainder if we add +2 to 21 (i.e. 1058 it gives 23 as the remainder when it gets divided by 23) and it 23 get divided by 23 yields zero "0".