# Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
2
3
18
21
None of these
Explanation:
``` 23) 1056 (45
92
---
136
115
---
21
---

Required number = (23 - 21)
= 2.
```
Discussion:
72 comments Page 1 of 8.

Leah said:   2 weeks ago
Got the answer now. Thanks, everyone for the explanation.
(1)

Suvarnii said:   11 months ago
Since,
23 * 46 = 1058.
And the given number is 1056,
1058 - 1056 = 2 is the answer.
(6)

Partha said:   12 months ago
@All.

The solution is

Adding the first option 2 with 1054 then we get 1056 when it is divided by 23 it gives the perfect number 46.

Doing this same procedure for all the options we get the answer in point. So, the first option is correct.
(2)

Shivamgi said:   2 years ago
What least number should be added to 94 so that the sum is completely divisible by 4?

Can anyone answer this?
(8)

Prajakta said:   2 years ago
What least number must be added to 1056
=1056+2= 1058.

So that the sum is completely divisible by 23?

1058Ã·23= remainder is 0.

So, the answer is 2.

When we add to.. Then this value is divisible by 23.
(1)

Jyoti said:   2 years ago
First divide 1056 by 23.
Remainder = 21
If we want 1056 totally divisible by 23 so we must add 2 to remainder 21 to make it 23.
Now the remainder is zero.
So, the correct answer is 2.
(18)

Suji said:   4 years ago
@Payal.

It's 797.
When we add it to 5678 we get 35 as rem.
On dividing the sum by 460.
(1)

King Ali said:   4 years ago
Let's make it simpler,

23*23 = 529.

To get a number closer to 1056.

529*2 = 1058.

What do we need to add to 1056 to make 1058?
1058-1056 = 2.
(7)

Ashwini said:   4 years ago
Whenever we divide any no then we want to break that no in such a group that each group contains equal no of elements.

For eg: If I divide 20/10 means I want to divide 20 in such groups that each group contains 10 elements here we get 2 is a no of groups that is our quotient. 20 is totally divided by 10 hence remainder is zero. In the above example (1056/23) also we have to break 1056 in groups of 23 elements. After division, it gives the remainder of 21 and quotient is 45. It is clear that if I add 2 more elements in a group of 21 then only I will get the 46th group of 23 elements and also get the no which is fully divided by 23.

So, 1056 + 2 = 1058 and 1058/23 gives quotient 46 and remainder as 0.
(2)

Meet said:   4 years ago
How can 1056-92 be 136?

It comes 964.
(1)