# Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 4)

4.

What least number must be added to 1056, so that the sum is completely divisible by 23 ?

Answer: Option

Explanation:

23) 1056 (45 92 --- 136 115 --- 21 --- Required number = (23 - 21) = 2.

Discussion:

72 comments Page 1 of 8.
Loverboy said:
1 decade ago

Explain?

Jarun james said:
1 decade ago

Explain more.

Abhisek said:
1 decade ago

Will you please elaborate?.

Karthi said:
1 decade ago

The value 92, 45 how it comes.

Explain.

Explain.

Deepika said:
1 decade ago

To find the correct no to add in amt 1056 it is divided by 23 to like 23*4 = 92 & its minus from 1056 then it remains 136 then its divided by 23*5 = 115 & minus from 136 then the remaining amt is 21 so there must be add 2 no.(21+2=23) so the ramaining amt will be zero.

Jomon said:
1 decade ago

1056/23=45.91

23*45=1035

1056-1035=21

Therefore 23-21=2

Ans =2

23*45=1035

1056-1035=21

Therefore 23-21=2

Ans =2

(1)

Nikitha said:
1 decade ago

It is so easy..

If the number 1056 is completely divisible by 23 means, remainder should come zero..

But if we divide 1056 by 23, the remainder is 2..

So if 2 is added to the 1056, we get remainder 0.

Therefore solution is 2

If the number 1056 is completely divisible by 23 means, remainder should come zero..

But if we divide 1056 by 23, the remainder is 2..

So if 2 is added to the 1056, we get remainder 0.

Therefore solution is 2

Vijay yadav said:
1 decade ago

@Nikitha nice and thanks.

Archana said:
1 decade ago

Very nice answer deepika. I am understood.

Hamsitha said:
1 decade ago

Very good answer nikitha.

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