# Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
2
3
18
21
None of these
Explanation:
``` 23) 1056 (45
92
---
136
115
---
21
---

Required number = (23 - 21)
= 2.
```
Discussion:
72 comments Page 2 of 8.

Js parihar said:   4 years ago
1056/23.

The simple method is;
The digit sum of 1056 = 12 = 3,
The digit sum of 23 = 5.

So what must be added to 3 to be divisible by 5 i.e 2 is the correct answer.
(6)

Muthu said:   4 years ago
@ALL.

As per my method.

10 * 23 = 2300
2300/2 = 1150
1150-1056 = 94
94/23 = 4 quotient balance 2 ans is 2.

Soura said:   5 years ago
@Mohanagiri.

Smart approach, Thanks.

Shubhada Lokhande said:   5 years ago
Basically we have to %(mod) operation here;

1056%23=
1056/23=45.91=46.
46*23=1058.

Satish chandra said:   5 years ago
When 1056 divided by 23 it yields 21 but we need to get "0" as remainder if we add +2 to 21 (i.e. 1058 it gives 23 as the remainder when it gets divided by 23) and it 23 get divided by 23 yields zero "0".

MohanaGiri said:   5 years ago
Simple,

They are asking only which is a least number make 1056 becomes divisible by 23.
So, we know divisibility means the remainder will be zero.

First, divide the1056 by 23.

And; we know 23*6=138, hence the given number 105(6) is must be 105(8) then we divided). Hence add 2 finally we get remainder zero.

Sathish said:   5 years ago
Why we did 23-21?

Ankur said:   5 years ago
@Nandi.

Please apply same formula in 1045 instead of 1056, 23 will remain same.

Sunny said:   5 years ago
@Nikitha.

But the reminder is not 2 how it comes 2?

Nandi Vishal said:   5 years ago
The best way lets assume 1056 to be 1+0+5+6=12=1+2=3 --> 1.
23=2+3=5 --> 2.

Hence 2 must be added to (1) to get completely divisible by 23.
(1)