Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Answer: Option
Explanation:
23) 1056 (45
92
---
136
115
---
21
---
Required number = (23 - 21)
= 2.
Discussion:
73 comments Page 3 of 8.
Nandi Vishal said:
8 years ago
The best way lets assume 1056 to be 1+0+5+6=12=1+2=3 --> 1.
23=2+3=5 --> 2.
Hence 2 must be added to (1) to get completely divisible by 23.
23=2+3=5 --> 2.
Hence 2 must be added to (1) to get completely divisible by 23.
(1)
Nkumar said:
8 years ago
1056+2=1058, it is completely divided by 23, so difference no. 1056-1058 =2, because 1058/23 =46.
Astik said:
8 years ago
1056/23.
=23/1056/46
92
-----------
136
138
-------------
When we multiply 23*5=115.
2
But I take one 1 more bigger digit I multiply 23*6=138
Difference of this two numbers is 2.
This is the simplest way.
=23/1056/46
92
-----------
136
138
-------------
When we multiply 23*5=115.
2
But I take one 1 more bigger digit I multiply 23*6=138
Difference of this two numbers is 2.
This is the simplest way.
Adithya said:
8 years ago
Hi Guys, it is simple first calculate 23*46 = 1058, Then see our number it is 1056, So to get remainder as Zero we need to add 2.
Nancy said:
8 years ago
How you got this 23-21=2?
Tony said:
8 years ago
1+0+5+6 = 12 = 1+2 = 3.
So given divisor is 23=2+3=5.
So to make a dividend to multiple of 5, add 2 to 3, it gives 5.
So given divisor is 23=2+3=5.
So to make a dividend to multiple of 5, add 2 to 3, it gives 5.
Nazar said:
8 years ago
Thank you @Nikitha.
Good explanation.
Good explanation.
Nirmal said:
8 years ago
I don't understand please anyone help me.
Blessy said:
9 years ago
Explained well, Thanks @Navin Kumar.
Anil said:
9 years ago
What must be added to 23/5 to get 4 1/2?
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