Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Answer: Option
Explanation:
23) 1056 (45
92
---
136
115
---
21
---
Required number = (23 - 21)
= 2.
Discussion:
73 comments Page 2 of 8.
Prajakta said:
4 years ago
What least number must be added to 1056
=1056+2= 1058.
So that the sum is completely divisible by 23?
1058/23= remainder is 0.
So, the answer is 2.
When we add to.. Then this value is divisible by 23.
=1056+2= 1058.
So that the sum is completely divisible by 23?
1058/23= remainder is 0.
So, the answer is 2.
When we add to.. Then this value is divisible by 23.
(11)
Prashant said:
1 decade ago
Digital sum method works here:
1056+2 = 1058--- 5 (digital sum).
1056+18 = 1074---3.
1056+3 = 1059-- 6.
1077+21 = 1098--9.
And the digital sum of 23 is 5. So option (A) is correct.
1056+2 = 1058--- 5 (digital sum).
1056+18 = 1074---3.
1056+3 = 1059-- 6.
1077+21 = 1098--9.
And the digital sum of 23 is 5. So option (A) is correct.
Jyoti said:
5 years ago
First divide 1056 by 23.
Remainder = 21
If we want 1056 totally divisible by 23 so we must add 2 to remainder 21 to make it 23.
Now the remainder is zero.
So, the correct answer is 2.
Remainder = 21
If we want 1056 totally divisible by 23 so we must add 2 to remainder 21 to make it 23.
Now the remainder is zero.
So, the correct answer is 2.
(42)
Rupesh said:
1 decade ago
Consider first 3 digits 105.
23*4=92; 105-92=13.
Now 13 & remaining digit 6 forms 136.
23*5=115; 136-115=21.
If we are adding 2 in 21 then it will completely divisible.
23*4=92; 105-92=13.
Now 13 & remaining digit 6 forms 136.
23*5=115; 136-115=21.
If we are adding 2 in 21 then it will completely divisible.
Js parihar said:
7 years ago
1056/23.
The simple method is;
The digit sum of 1056 = 12 = 3,
The digit sum of 23 = 5.
So what must be added to 3 to be divisible by 5 i.e 2 is the correct answer.
The simple method is;
The digit sum of 1056 = 12 = 3,
The digit sum of 23 = 5.
So what must be added to 3 to be divisible by 5 i.e 2 is the correct answer.
(10)
Abhijit Mukherjee said:
1 decade ago
@Nikitha please explain it.
But if we divide 1056 by 23, the remainder is 2.
So if 2 is added to the 1056, we get remainder 0.
Therefore solution is 2.
But if we divide 1056 by 23, the remainder is 2.
So if 2 is added to the 1056, we get remainder 0.
Therefore solution is 2.
King Ali said:
6 years ago
Let's make it simpler,
23*23 = 529.
To get a number closer to 1056.
529*2 = 1058.
What do we need to add to 1056 to make 1058?
1058-1056 = 2.
23*23 = 529.
To get a number closer to 1056.
529*2 = 1058.
What do we need to add to 1056 to make 1058?
1058-1056 = 2.
(17)
Kshama Jain said:
9 years ago
Firstly what @Nikitha has explained is wrong. Because the remainder is 21 not 2. So please can somebody give me the answer why we did 23 - 21?
Nandi Vishal said:
8 years ago
The best way lets assume 1056 to be 1+0+5+6=12=1+2=3 --> 1.
23=2+3=5 --> 2.
Hence 2 must be added to (1) to get completely divisible by 23.
23=2+3=5 --> 2.
Hence 2 must be added to (1) to get completely divisible by 23.
(1)
Bluemoon said:
1 decade ago
I don't understand why we should do 23-21 at the end can anyone explain this. And @Nikitha 2 is not the remainder. 21 is the remainder.
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