Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 4)

Numbers

What least number must be added to 1056, so that the sum is completely divisible by 23 ?

None of these

Answer: Option

Explanation:

 23) 1056 (45
      92
      ---
      136
      115
      ---
       21
      ---
     
 Required number = (23 - 21)    
                 = 2.

Discussion:

73 comments Page 3 of 8.

HMT said: 1 decade ago

If we do 1056/23. Then remainder = 21.

= 23-21 = 2.

Because to make 23 we have to add 2 in remainder. So we can do 23/23 which is 0.

Adithya said: 8 years ago

Hi Guys, it is simple first calculate 23*46 = 1058, Then see our number it is 1056, So to get remainder as Zero we need to add 2.

Anzer Hussain said: 9 years ago

1056/23 = 45.91.
So round of the figure of the result that means 46.
Then 46 * 23 = 1058.

=> 1058 - 1056 = 2.

The answer is 2.

Tony said: 8 years ago

1+0+5+6 = 12 = 1+2 = 3.
So given divisor is 23=2+3=5.
So to make a dividend to multiple of 5, add 2 to 3, it gives 5.

Shivamgi said: 4 years ago

What least number should be added to 94 so that the sum is completely divisible by 4?

Can anyone answer this?

(28)

Muthu said: 7 years ago

@ALL.

As per my method.

10 * 23 = 2300
2300/2 = 1150
1150-1056 = 94
94/23 = 4 quotient balance 2 ans is 2.

Shubhada Lokhande said: 7 years ago

Basically we have to %(mod) operation here;

1056%23=
1056/23=45.91=46.
46*23=1058.
1058-1056=2 => answer.

(1)

Mitali said: 9 years ago

This digital root method is nice and quick. Does it work for all questions, where else can this be applied?

Payal said: 9 years ago

What must be added to 5678 to gives a remainder 35when divided by 460?

Please help me to get the solution.

Nkumar said: 8 years ago

1056+2=1058, it is completely divided by 23, so difference no. 1056-1058 =2, because 1058/23 =46.

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