Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Answer: Option
Explanation:
23) 1056 (45
92
---
136
115
---
21
---
Required number = (23 - 21)
= 2.
Discussion:
74 comments Page 2 of 8.
Suji said:
6 years ago
@Payal.
It's 797.
When we add it to 5678 we get 35 as rem.
On dividing the sum by 460.
It's 797.
When we add it to 5678 we get 35 as rem.
On dividing the sum by 460.
(2)
Shubhada Lokhande said:
7 years ago
Basically we have to %(mod) operation here;
1056%23=
1056/23=45.91=46.
46*23=1058.
1058-1056=2 => answer.
1056%23=
1056/23=45.91=46.
46*23=1058.
1058-1056=2 => answer.
(1)
Anandhi Yesubalan said:
4 months ago
@All.
I have a doubt after dividing 1058 by 23 we got 46.
After 46 how to calculate this, please someone explain me.
I have a doubt after dividing 1058 by 23 we got 46.
After 46 how to calculate this, please someone explain me.
(1)
MohanaGiri said:
8 years ago
Simple,
They are asking only which is a least number make 1056 becomes divisible by 23.
So, we know divisibility means the remainder will be zero.
First, divide the1056 by 23.
And; we know 23*6=138, hence the given number 105(6) is must be 105(8) then we divided). Hence add 2 finally we get remainder zero.
They are asking only which is a least number make 1056 becomes divisible by 23.
So, we know divisibility means the remainder will be zero.
First, divide the1056 by 23.
And; we know 23*6=138, hence the given number 105(6) is must be 105(8) then we divided). Hence add 2 finally we get remainder zero.
(1)
Sunny said:
8 years ago
@Nikitha.
But the reminder is not 2 how it comes 2?
But the reminder is not 2 how it comes 2?
(1)
Nandi Vishal said:
8 years ago
The best way lets assume 1056 to be 1+0+5+6=12=1+2=3 --> 1.
23=2+3=5 --> 2.
Hence 2 must be added to (1) to get completely divisible by 23.
23=2+3=5 --> 2.
Hence 2 must be added to (1) to get completely divisible by 23.
(1)
Ragu said:
1 decade ago
Hi dude.
We have 4 choices in question paper.
Firs to add 1056+2 = 1058, 1058/23 = 0, we got no remaining in finally.
1056+3 = 1059, 1059/23 = 1 we gotta remaining.
1056+18 = 1074, 1074/23 = 16, same like got remaining.
Finally 1056+21 = 1077, 1077/23 = 19, same like got remaining.
Ans = 2.
We have 4 choices in question paper.
Firs to add 1056+2 = 1058, 1058/23 = 0, we got no remaining in finally.
1056+3 = 1059, 1059/23 = 1 we gotta remaining.
1056+18 = 1074, 1074/23 = 16, same like got remaining.
Finally 1056+21 = 1077, 1077/23 = 19, same like got remaining.
Ans = 2.
(1)
Meet said:
7 years ago
How can 1056-92 be 136?
It comes 964.
It comes 964.
(1)
Jomon said:
1 decade ago
1056/23=45.91
23*45=1035
1056-1035=21
Therefore 23-21=2
Ans =2
23*45=1035
1056-1035=21
Therefore 23-21=2
Ans =2
(1)
Raghavi said:
9 years ago
@Sankar & @Prashant.
Is the digital root method is applicable for all the divisors?
Is the digital root method is applicable for all the divisors?
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