Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Answer: Option
Explanation:
23) 1056 (45
92
---
136
115
---
21
---
Required number = (23 - 21)
= 2.
Discussion:
76 comments Page 6 of 8.
Hamsitha said:
1 decade ago
Very good answer nikitha.
Archana said:
2 decades ago
Very nice answer deepika. I am understood.
Vijay yadav said:
2 decades ago
@Nikitha nice and thanks.
Nikitha said:
2 decades ago
It is so easy..
If the number 1056 is completely divisible by 23 means, remainder should come zero..
But if we divide 1056 by 23, the remainder is 2..
So if 2 is added to the 1056, we get remainder 0.
Therefore solution is 2
If the number 1056 is completely divisible by 23 means, remainder should come zero..
But if we divide 1056 by 23, the remainder is 2..
So if 2 is added to the 1056, we get remainder 0.
Therefore solution is 2
Deepika said:
2 decades ago
To find the correct no to add in amt 1056 it is divided by 23 to like 23*4 = 92 & its minus from 1056 then it remains 136 then its divided by 23*5 = 115 & minus from 136 then the remaining amt is 21 so there must be add 2 no.(21+2=23) so the ramaining amt will be zero.
Karthi said:
2 decades ago
The value 92, 45 how it comes.
Explain.
Explain.
Abhisek said:
2 decades ago
Will you please elaborate?.
Jarun james said:
2 decades ago
Explain more.
Lavanya Sankari said:
1 decade ago
I can understand it very clearly.
Loverboy said:
2 decades ago
Explain?
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