Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Answer: Option
Explanation:
23) 1056 (45
92
---
136
115
---
21
---
Required number = (23 - 21)
= 2.
Discussion:
76 comments Page 6 of 8.
HMT said:
1 decade ago
If we do 1056/23. Then remainder = 21.
= 23-21 = 2.
Because to make 23 we have to add 2 in remainder. So we can do 23/23 which is 0.
= 23-21 = 2.
Because to make 23 we have to add 2 in remainder. So we can do 23/23 which is 0.
Prashant said:
1 decade ago
Digital sum method works here:
1056+2 = 1058--- 5 (digital sum).
1056+18 = 1074---3.
1056+3 = 1059-- 6.
1077+21 = 1098--9.
And the digital sum of 23 is 5. So option (A) is correct.
1056+2 = 1058--- 5 (digital sum).
1056+18 = 1074---3.
1056+3 = 1059-- 6.
1077+21 = 1098--9.
And the digital sum of 23 is 5. So option (A) is correct.
Rocky said:
1 decade ago
23*46 = 1058.
Therefore if we add 2 to 1056 then it is divisible by 23.
Therefore if we add 2 to 1056 then it is divisible by 23.
Ankita said:
1 decade ago
Consider the number 13. When we divide it by 6, the remainder is 1. Now, what must be added to 13 to make it completely divisible by 6?
12 is completely divisible by 6. We must add 6 more to 12 to make it divisible by 6. While dividing by 13, the remainder is 1. So we add 5 (6-1) more to make the number 13 divisible by 6.
Similarly in this case, we add 2 (23-21).
12 is completely divisible by 6. We must add 6 more to 12 to make it divisible by 6. While dividing by 13, the remainder is 1. So we add 5 (6-1) more to make the number 13 divisible by 6.
Similarly in this case, we add 2 (23-21).
Rupesh said:
1 decade ago
Consider first 3 digits 105.
23*4=92; 105-92=13.
Now 13 & remaining digit 6 forms 136.
23*5=115; 136-115=21.
If we are adding 2 in 21 then it will completely divisible.
23*4=92; 105-92=13.
Now 13 & remaining digit 6 forms 136.
23*5=115; 136-115=21.
If we are adding 2 in 21 then it will completely divisible.
Navin kumar kamti said:
1 decade ago
1056/23 = 45.91.
45*23 = 1035.
Now we can write 1035+23 = 1058.
Hence,
1058-1056 = 2.
45*23 = 1035.
Now we can write 1035+23 = 1058.
Hence,
1058-1056 = 2.
Raj said:
1 decade ago
1056/23 = 45.91.
0.91*23 = 20.93 = 21(approx).
23-21 = 2.
0.91*23 = 20.93 = 21(approx).
23-21 = 2.
Roshinphilips said:
1 decade ago
1056/23 = 45.xx,
45*23 = 1035,
1035+23 = 1058.
Difference between 1056 and 1058 = 2.
45*23 = 1035,
1035+23 = 1058.
Difference between 1056 and 1058 = 2.
Himanshu jain said:
1 decade ago
Will you please explain it a little bit better?
Bluemoon said:
1 decade ago
I don't understand why we should do 23-21 at the end can anyone explain this. And @Nikitha 2 is not the remainder. 21 is the remainder.
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