Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Answer: Option
Explanation:
23) 1056 (45
92
---
136
115
---
21
---
Required number = (23 - 21)
= 2.
Discussion:
73 comments Page 7 of 8.
Hanipoo23 said:
1 decade ago
Thank you nikitha.
Jaldhi said:
1 decade ago
Why are we first dividing aren't we suppose to add the least number?
Suba said:
1 decade ago
23x45=1035 so 1056-1035=21 so the number 23-21=2 this is the answer
Hamsitha said:
1 decade ago
Very good answer nikitha.
Archana said:
1 decade ago
Very nice answer deepika. I am understood.
Vijay yadav said:
1 decade ago
@Nikitha nice and thanks.
Nikitha said:
1 decade ago
It is so easy..
If the number 1056 is completely divisible by 23 means, remainder should come zero..
But if we divide 1056 by 23, the remainder is 2..
So if 2 is added to the 1056, we get remainder 0.
Therefore solution is 2
If the number 1056 is completely divisible by 23 means, remainder should come zero..
But if we divide 1056 by 23, the remainder is 2..
So if 2 is added to the 1056, we get remainder 0.
Therefore solution is 2
Jomon said:
1 decade ago
1056/23=45.91
23*45=1035
1056-1035=21
Therefore 23-21=2
Ans =2
23*45=1035
1056-1035=21
Therefore 23-21=2
Ans =2
(1)
Deepika said:
1 decade ago
To find the correct no to add in amt 1056 it is divided by 23 to like 23*4 = 92 & its minus from 1056 then it remains 136 then its divided by 23*5 = 115 & minus from 136 then the remaining amt is 21 so there must be add 2 no.(21+2=23) so the ramaining amt will be zero.
Karthi said:
1 decade ago
The value 92, 45 how it comes.
Explain.
Explain.
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