Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 4)
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
2
3
18
21
None of these
Answer: Option
Explanation:
 23) 1056 (45
      92
      ---
      136
      115
      ---
       21
      ---
     
 Required number = (23 - 21)    
                 = 2.   
Discussion:
73 comments Page 5 of 8.

Amit said:   9 years ago
Nice trick @Sankar.

Gayatri said:   9 years ago
Nikitha has explained well that everyone can understand easily.

Thank you @Nikitha.

Lavanya Sankari said:   10 years ago
I can understand it very clearly.

Bhupendra said:   10 years ago
23^2 = 529.

And 529x2 = 1058.

Given 1056, difference = 2.

Dinesh said:   1 decade ago
Very good platform provided you mam to understand the problem. Really very nice!

Ragu said:   1 decade ago
Hi dude.

We have 4 choices in question paper.

Firs to add 1056+2 = 1058, 1058/23 = 0, we got no remaining in finally.

1056+3 = 1059, 1059/23 = 1 we gotta remaining.

1056+18 = 1074, 1074/23 = 16, same like got remaining.

Finally 1056+21 = 1077, 1077/23 = 19, same like got remaining.

Ans = 2.
(1)

Abhijit Mukherjee said:   1 decade ago
@Nikitha please explain it.

But if we divide 1056 by 23, the remainder is 2.

So if 2 is added to the 1056, we get remainder 0.

Therefore solution is 2.

HMT said:   1 decade ago
If we do 1056/23. Then remainder = 21.

= 23-21 = 2.

Because to make 23 we have to add 2 in remainder. So we can do 23/23 which is 0.

Prashant said:   1 decade ago
Digital sum method works here:

1056+2 = 1058--- 5 (digital sum).

1056+18 = 1074---3.

1056+3 = 1059-- 6.

1077+21 = 1098--9.

And the digital sum of 23 is 5. So option (A) is correct.

Rocky said:   1 decade ago
23*46 = 1058.

Therefore if we add 2 to 1056 then it is divisible by 23.


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