Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 1)
1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Answer: Option
Explanation:
Let AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, 
ACB = 30° and ADB = 45°.
| AB | = tan 30° = | 1 |  AC = AB x 3 = 1003 m. |
| AC | 3 |
| AB | = tan 45° = 1 AD = AB = 100 m. |
| AD |
 CD = (AC + AD) |
= (1003 + 100) m |
| = 100(3 + 1) | |
| = (100 x 2.73) m | |
| = 273 m. |
Discussion:
104 comments Page 4 of 11.
Kanishka Roy said:
5 years ago
How do you decide which is the base and which is the height? Explain it, please.
Anish kumar said:
1 decade ago
We can also able to find the answer using sin and cos. But more step is needed.
(1)
Kishor said:
7 years ago
How? tan 45° = 1
AD = AB = 100 m. How it is? Explain in detail.
AD = AB = 100 m. How it is? Explain in detail.
Uzma said:
2 years ago
Why we are using tan while we have to find the distance?
i.e why tan =1/√3?
i.e why tan =1/√3?
(3)
Swapnil said:
8 years ago
How to find root3 value, please explain in detail. How to come 1.732?
Mythili said:
5 years ago
@Yeshi Samdup
How?
CA = 100/tan30,
CA = 173.
Please explain this.
How?
CA = 100/tan30,
CA = 173.
Please explain this.
(2)
Kavya sreeram said:
9 years ago
Tan 30 is 1/√3 right? then in all problem, it is 1, how come?
Jowy said:
1 decade ago
The tan30 is root(3) divide by 3. So how did you get root(3) ?
Prasad said:
1 decade ago
How to solve the problem I am not under standing for Tan value.
Ram said:
9 years ago
I do not understand. Please, anyone, give a simple explanation.
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