Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 1)
1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Answer: Option
Explanation:
Let AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, 
ACB = 30° and ADB = 45°.
| AB | = tan 30° = | 1 |  AC = AB x 3 = 1003 m. |
| AC | 3 |
| AB | = tan 45° = 1 AD = AB = 100 m. |
| AD |
 CD = (AC + AD) |
= (1003 + 100) m |
| = 100(3 + 1) | |
| = (100 x 2.73) m | |
| = 273 m. |
Discussion:
104 comments Page 5 of 11.
ROHIT said:
8 years ago
I don't understand the answer. Please anyone help me to get it.
Praket Mishra said:
6 years ago
Where we should use sin, cos, tan? Please anyone explain me.
(1)
Mrinayak said:
6 years ago
How to find the √3 value? Please explain the process.
Sahil said:
1 decade ago
How to calculate (root 3 + 1) manually, is there any way ?
Shro said:
1 decade ago
@Sahil
square root of 3 is 1.73.
So ,add 1.73 + 1 = 2.73
square root of 3 is 1.73.
So ,add 1.73 + 1 = 2.73
Pranso said:
9 years ago
Great explanation, thank you so much for all your answers.
Sehdev said:
8 years ago
How we calculated the square root of 3 that we got 1.73?
Kushal Neupane said:
8 years ago
How we calculated the square root of 3 that wu got 1.73?
Uttam Singh said:
7 years ago
We can use a Divide rule to find the root of any number.
(1)
MANI said:
8 years ago
How can you take √3 is 1.732? Can anyone explain?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers