Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 6)
6.
If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Sunday
Saturday
Tuesday
Wednesday
Answer: Option
Explanation:

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.

The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.

Given that, 6th March, 2005 is Monday.

6th March, 2004 is Sunday (1 day before to 6th March, 2005).

Discussion:
112 comments Page 9 of 12.

Akshay patil said:   10 years ago
2005 - 2004 + 1 (leap year) = 2/7.
= 2 remainder.

So, back to two days and it's a Saturday.

Kannaiah said:   10 years ago
Jan (1), Feb (4), Mar (4), Apr (0), May (2), Jun (5), Jul (0), Aug (3), Sep (6), Oct (1), Nov (4), Dec (6).

Weeks:

Sun (1), Mon (2), Tues (3), Wed (4), Thurs (5) Fri (6), Sat (0 or 7).

Year c: 1800-2. 1900-0. 2000-6.

6+4+4+1+6 = 21.

7)21(3 = 0.

My Answer = Saturday.

Then how it's Sunday. Please explain me.

Nitin said:   10 years ago
Hey guys according to the calendar that day is a Saturday.

Jyoo said:   10 years ago
Please tell me using year code month code short cut way.

Saintclem said:   10 years ago
@Amit pal has given the best and most simple explanation anyone can give here. Always remember this. Keep it simple!

Amit pal said:   1 decade ago
First all find actual day on 6th march 2004 that is Saturday.

Find day on 6th march 2005 that is Sunday in actual.

But they shift it by 1 day as Monday.

(So in your answer you should also shift it by one day).

Than it becomes Sunday.

JITENDRA PAL said:   1 decade ago
Guys even you can find through vedic maths.

I show you there are codes for solving calendar problems:

Months:

Jan (1) , feb (4) , mar (4) , apr (0) , may (2) , jun (5) , jul (0) , aug (3) , sep (6) , oct (1) , nov (4) , dec (6). Learn it through any trick.

Weeks:

Sun (1), mon (2), tues (3) fri (6), satur (0 or 7).

Start:

Check if condition: 6th march 2005.

Step : 6 (date) + 4 (march code) + 05 (year) + 05 (date) /4 = 6+4+5+1 = 16/7 = 2 odd days means (monday) but year is 20th century so, -1 is apply that's means 2 - 1 = 1 odd day which means sunday. But option said monday that's means add +1 means 1+1 = 2 odd days (monday).

Check then condition: 6th march 2004.

Step : 6 (date) + 4 (march code) + 04 (year) + 04 (year) /4 = 6+4+4+1 = 15/7 = 1 odd days means (sunday) but year is 20th century so, -1 is apply that's means 1-1 = 0 odd (saturday) but 2004 is leap year means again -1 that's means 6 odd (friday) but from if condition we add +1 at last according to question. It means we will +1 here also then 6 + 1 = 7 or 0 odd day means saturday.

All the best guys.

Manish said:   1 decade ago
Answer is wrong. Its Saturday. Check in calendar. 2004 is leap year so odd days should be 2 not 1.

Sumanth geras said:   1 decade ago
Hi @Roji I can explain by your formula.

Day+Month code+(x-1990)+(x-1990)/4.

Step 1: First you should calculate the day for the first mentioned date.

i.e 4 for 6th march 2005.

[6+4+105+26=141/7 it should be Sunday since rem is 1].

But it was given Monday so it is shifted by one day.

Step 2: If you calculate for 6th mar' 2004 you will get Saturday.

So to get answer you should shift the obtained answer by one day. It works for all problems.

Anees said:   1 decade ago
Any given year is divisible by the number 4 is a leap year, pretty simple.

For e.g 2008/4 = 502 (NO REMAINDER).

2007/4 = 501.75 (REMAINDER).

Just do observe it's too simple.


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