Exercise :: Calendar - General Questions
- Calendar - Important Formulas
- Calendar - General Questions
6. | If 6^{th} March, 2005 is Monday, what was the day of the week on 6^{th} March, 2004? |
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Answer: Option A Explanation: The year 2004 is a leap year. So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only. The day on 6^{th} March, 2005 will be 1 day beyond the day on 6^{th} March, 2004. Given that, 6^{th} March, 2005 is Monday. 6^{th} March, 2004 is Sunday (1 day before to 6^{th} March, 2005). |
7. | On what dates of April, 2001 did Wednesday fall? |
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Answer: Option D Explanation:
We shall find the day on 1^{st} April, 2001.
1^{st} April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001) Odd days in 1600 years = 0 Odd days in 400 years = 0
Jan. Feb. March April Total number of odd days = (0 + 0 + 0) = 0 On 1^{st} April, 2001 it was Sunday. In April, 2001 Wednesday falls on 4^{th}, 11^{th}, 18^{th} and 25^{th}. |
8. | How many days are there in x weeks x days? |
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Answer: Option B Explanation: x weeks x days = (7x + x) days = 8x days. |
9. | The last day of a century cannot be |
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Answer: Option C Explanation: 100 years contain 5 odd days. Last day of 1^{st} century is Friday. 200 years contain (5 x 2) 3 odd days. Last day of 2^{nd} century is Wednesday. 300 years contain (5 x 3) = 15 1 odd day. Last day of 3^{rd} century is Monday. 400 years contain 0 odd day. Last day of 4^{th} century is Sunday. This cycle is repeated. Last day of a century cannot be Tuesday or Thursday or Saturday. |
10. | On 8^{th} Feb, 2005 it was Tuesday. What was the day of the week on 8^{th} Feb, 2004? |
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Answer: Option C Explanation: The year 2004 is a leap year. It has 2 odd days. The day on 8^{th} Feb, 2004 is 2 days before the day on 8^{th} Feb, 2005. Hence, this day is Sunday. |