Aptitude - Calendar - Discussion

Every century has this one
100 = 5odd days=>friday.
200 = 3odd days=>wednesday.
300 = 1odd days=>monday.
400 = 0 odd days=>sunday.

Remainig=>(tuesday,thusday,saturday)=>tuesday only is their so correct answer is Tuesday.

Every century has this one
100 = 5odd days=>friday.
200 = 3odd days=>wednesday.
300 = 1odd days=>monday.
400 = 0 odd days=>sunday.

Remainig=>(tuesday,thusday,saturday)=>tuesday only is their so correct answer is Tuesday.

100 years = 24 leap years + 76 ordinary years.
= (24*2) +(76*1).
= 124 odd days.
= 124÷7.
=(17 weeks) +5odd days
= 5(Friday).
200 years =5*2=10
=1 week + 3odd days
=3(Wednesday).

300 years=5*3=15.
=2 weeks + 1 odd day.
=1 (Monday).

No, this is wrong: because the day on 31st December 1799 was a Tuesday (So last day of century can be a Tuesday as of 17th century last day was Tuesday).

No. Off odd days in 100 years = 5;
But only from 1601 to 1700 (as 1700 is divisible by 4 but not by 400 hence not leap year) BUT No. Off odd days in 100 years = 6 from 1600 to 1699 (as 1600 is a leap year so 25 leap years and 75 normal so 6 odd days).

Hence: The last days are Friday + 6 odd days = Thursday (6odd days because the here year 1400, 1600, 2000 is considered).

Thursday + 5 odd days = Tuesday.

Tuesday + 5 odd days = Sunday.

Sunday + 5 odd days = Friday.

For confirmation please check actual days: the day on 31st December 1599 is Friday; a day on 31st December 1699 is Thursday; a day on 31st December 1799 is Tuesday; day on 31st December 1899 is Sunday; a day on 31st December 1999 is Friday.

@All.

Remember that the last day of the century can't be Tuesday, Thursday and Saturday.

The question is to find the one that not end with a century then we need to find which days will end with a century.

100/7 = (remainder 2 therefore Monday)
200/7 = (rem 4 therefore wed)
300/7(rem 6 therefore Friday)
400/7 = (rem 0 so Saturday)

Tuesday the only one day given in the options which don't end in a century.

I hope it was easy to understand.

I'm taking the solution as:

100/7=14 remainder 2. ie Tuesday.

Century (100,200,300) has no leap years. So we did not get 2 as odd day i.e., Tuesday.

2 and 1 are taken for odd days of leap year and ordinary year respectively.

@Meena.

Thanks for your answer. Very helpful. But why is it 121*2 and 379*1? Could you please explain from where 2 and 1 are taken?