Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 10)
10.
On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
Answer: Option
Explanation:
The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday.
Discussion:
48 comments Page 1 of 5.
Chhotu kumar said:
1 month ago
0 = SUNDAY.
1 = MONDAY.
2 = TUESDAY.
3 = WEDNESDAY.
4 = THURSDAY.
5 = FRIDAY.
6 = SATURDAY.
We need to split that year of 2004.
=> 1600 + 400 + 3 + (Jan+8).
=> 0 + 0 + 3(1) + (3+8).(Here January Have 3 odd day then also we put 3 in there).
Substitute all the values.
3 + 3 + 8 = 14(day).
=>14/7 =2(weeks)
=>2 weeks + 0 odd day.
So, the Answer is SUNDAY.
1 = MONDAY.
2 = TUESDAY.
3 = WEDNESDAY.
4 = THURSDAY.
5 = FRIDAY.
6 = SATURDAY.
We need to split that year of 2004.
=> 1600 + 400 + 3 + (Jan+8).
=> 0 + 0 + 3(1) + (3+8).(Here January Have 3 odd day then also we put 3 in there).
Substitute all the values.
3 + 3 + 8 = 14(day).
=>14/7 =2(weeks)
=>2 weeks + 0 odd day.
So, the Answer is SUNDAY.
Vinay Pratap Singh said:
2 years ago
@All.
Month code:
Jan -0
Feb- 3
March-3
April-6
May-1
June-4
July-6
Aug-2
Sep-5
Oct-0
Nov-3
Dec-5
Day code:
Sun-0,7
Mon-1
Tue-2
Wed-3
Thur-4
Fri-5
Sat-6
Year code:
1600-1699=6
1700-1799=4
1800-1899=2
1900-1999=0
2000-2999=6
By using the formula,
Formula = Day code + Month code + Year code + (x-1900) + (x-1900)/4.
Our qn is : 8th Feb 2004.
=> 8+3+6+104+104/4.
=>8+3+6+104+26.
=>147.
Since there 7 days in a week divide 147 by 7.
So, 147/7 =>0 remainder.
0=>Sunday.
Month code:
Jan -0
Feb- 3
March-3
April-6
May-1
June-4
July-6
Aug-2
Sep-5
Oct-0
Nov-3
Dec-5
Day code:
Sun-0,7
Mon-1
Tue-2
Wed-3
Thur-4
Fri-5
Sat-6
Year code:
1600-1699=6
1700-1799=4
1800-1899=2
1900-1999=0
2000-2999=6
By using the formula,
Formula = Day code + Month code + Year code + (x-1900) + (x-1900)/4.
Our qn is : 8th Feb 2004.
=> 8+3+6+104+104/4.
=>8+3+6+104+26.
=>147.
Since there 7 days in a week divide 147 by 7.
So, 147/7 =>0 remainder.
0=>Sunday.
(8)
Jabbar jr said:
2 years ago
0 = SUNDAY.
1 = MONDAY.
2 = TUESDAY.
3 = WEDNESDAY.
4 = THURSDAY.
5 = FRIDAY.
6 = SATURDAY.
We need to split that year of 2004.
=> 1600 + 400 + 3 + (Jan+8).
=> 0 + 0 + 3(1) + (3+8). // (Here January Have 3 odd day then also we put 3 in there).
Substitute all the values.
3+3+8= 14 weeks + 0 odd day.
Answer is SUNDAY.
1 = MONDAY.
2 = TUESDAY.
3 = WEDNESDAY.
4 = THURSDAY.
5 = FRIDAY.
6 = SATURDAY.
We need to split that year of 2004.
=> 1600 + 400 + 3 + (Jan+8).
=> 0 + 0 + 3(1) + (3+8). // (Here January Have 3 odd day then also we put 3 in there).
Substitute all the values.
3+3+8= 14 weeks + 0 odd day.
Answer is SUNDAY.
(5)
Ritwik said:
2 years ago
Feb is included(as we know a leap year contains 2 odd days, Here when we are going backward from 8th feb 2005 to 8th feb 2004,it includes the feb month ) i.e the correct answer is Sunday.
(2)
Rohit kumar said:
2 years ago
Yes, This is the correct answer, MONDAY.
Because 2004 to 2005 is the ordinary year, so 1 odd day.
And Tuesday -1=Monday.
Because 2004 to 2005 is the ordinary year, so 1 odd day.
And Tuesday -1=Monday.
(19)
Ashok said:
3 years ago
According to me, the Correct answer is MONDAY.
Because the previous year is one day before next year so if 8th Feb 2005 is Tuesday then 8th feb 2004 will be Monday.
Because the previous year is one day before next year so if 8th Feb 2005 is Tuesday then 8th feb 2004 will be Monday.
(20)
Rinzin said:
4 years ago
The Correct option is Monday.
(12)
Katherin said:
5 years ago
I got the answer as Monday.
Formula = Day code + Month code + (x-1900) + (x-1900)/4.
Formula = Day code + Month code + (x-1900) + (x-1900)/4.
(5)
Swathi said:
5 years ago
2005 is an ordinary year then 1 0dd day so we can do subtract that odd day from Tuesday we get Monday, how we will get Sunday? can you plz explain clearly?
(3)
Firdous said:
6 years ago
Just memorie these tables:
Month code:
Jan -0
Feb- 3
March-3
April-6
May-1
June-4
July-6
Aug-2
Sep-5
Oct-0
Nov-3
Dec-5
Day code:
Sun-0,7
Mon-1
Tue-2
Wed-3
Thur-4
Fri-5
Sat-6
Year code:
1600-1699=6
1700-1799=4
1800-1899=2
1900-1999=0
2000-2999=6
By using the formula,
Formula = day code + month code + year code + (x-1900) + (x-1900)/4
Our qn is : 8th feb 2004.
=> 8+3+6+104+104/4.
=>8+3+6+104+26.
=>147.
Since there 7 days in a week so divide 147 by 7.
So, 147/7 =>0 remainder.
0=>sunday.
Month code:
Jan -0
Feb- 3
March-3
April-6
May-1
June-4
July-6
Aug-2
Sep-5
Oct-0
Nov-3
Dec-5
Day code:
Sun-0,7
Mon-1
Tue-2
Wed-3
Thur-4
Fri-5
Sat-6
Year code:
1600-1699=6
1700-1799=4
1800-1899=2
1900-1999=0
2000-2999=6
By using the formula,
Formula = day code + month code + year code + (x-1900) + (x-1900)/4
Our qn is : 8th feb 2004.
=> 8+3+6+104+104/4.
=>8+3+6+104+26.
=>147.
Since there 7 days in a week so divide 147 by 7.
So, 147/7 =>0 remainder.
0=>sunday.
(6)
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