Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 10)
10.
On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
Answer: Option
Explanation:
The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday.
Discussion:
48 comments Page 1 of 5.
Kavya said:
1 decade ago
I didn't understand exactly. Any one can please explain this to me.
Amit kumar said:
1 decade ago
It is simple date given 8th feb 2005, a 366 days before date is 8th feb 2004. Simple divide 366/7, we get 2 remainder. Then subtract 2 days from tuesday its sunday.
Ramya Rajesh said:
1 decade ago
Using formula, It is not correct The answer is monday.
So I didn't understand. So Please explain it by using the formula like day+ month No.+ X-1900+X-1900/4.
So I didn't understand. So Please explain it by using the formula like day+ month No.+ X-1900+X-1900/4.
Ramya Rajesh said:
1 decade ago
I Can't Understand Please explain it by using formula.
Kiruthika said:
1 decade ago
I can't understand using formula.
(1)
Amit AGarwal said:
1 decade ago
8+2+4+1-1=14/7
Remainder=0
Sunday.
Remainder=0
Sunday.
(1)
Sheelu said:
1 decade ago
How we know that year is leap or not ?
(1)
NEHA said:
1 decade ago
When a year is divisible by 4, then it is a leap year.
Ananda Masal said:
1 decade ago
Same calender repeats if it is.
1) leap year=+28yrs.
2) leap+1 year=+6yrs.
3) leap+2years=+11yrs.
4) leap+3year=+11yrs.
For exa. -.
1984=leap year.
Same calender repeats on 2012.
1) leap year=+28yrs.
2) leap+1 year=+6yrs.
3) leap+2years=+11yrs.
4) leap+3year=+11yrs.
For exa. -.
1984=leap year.
Same calender repeats on 2012.
(1)
Pragati said:
1 decade ago
Hey this takes quite a long time to find days of week like this. But competitive exams does not provide us such a long time. Please suggest me something.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers