Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 12 of 14.
Ganesh said:
7 years ago
3.2*10=32.
282-32=250.
250÷40=6.25.
282-32=250.
250÷40=6.25.
Brahmin Shrestha said:
7 years ago
Total over of match=10+40=50.
Total runs in 50 overs=282.
First 10 overs runs =3.2*10=32.
We have to calculate run rate of last 40 overs.
Now..run in 40 over= total run-10 over's run.
So, 282-32=250.
Run rate in 40 overs= run in 40 overs ÷overs.
=250÷40=6.25.
Hence, the required run rate in 40 is 6.25 answer.
Total runs in 50 overs=282.
First 10 overs runs =3.2*10=32.
We have to calculate run rate of last 40 overs.
Now..run in 40 over= total run-10 over's run.
So, 282-32=250.
Run rate in 40 overs= run in 40 overs ÷overs.
=250÷40=6.25.
Hence, the required run rate in 40 is 6.25 answer.
(2)
Leena said:
7 years ago
Nice explanation, thank you.
Red bull said:
7 years ago
Thanks @Pratik Mehta.
Raja said:
7 years ago
First we have to calculate the last 40 overs run rate.
Total score =282 but already they are scored in first 10 overs score was(10 * 3.2=32),
For these, we are subtracting,
Total score -10 overs score then (282-32) = 250.
Then we have get the score of last 40 over the score was 250.
Total score scored by last 40 overs/ number of overs.
250/40 = 6.25.
Total score =282 but already they are scored in first 10 overs score was(10 * 3.2=32),
For these, we are subtracting,
Total score -10 overs score then (282-32) = 250.
Then we have get the score of last 40 over the score was 250.
Total score scored by last 40 overs/ number of overs.
250/40 = 6.25.
(2)
Ajay Kumar said:
6 years ago
The first 10 overs run rate is 3.2 which means score will be taken 32 runs per 10 overs.
Target is 282 then 282-32=250 remaining 40 overs runs.
Finally 250/40=6.25.
Target is 282 then 282-32=250 remaining 40 overs runs.
Finally 250/40=6.25.
(2)
Rahul Vishwakarma said:
5 years ago
Left over = 40-10 = 30overs.
So, required run rate = (target /left over ) - current run rate.
= (282/30)- 3.2.
= 6.2.
So, required run rate = (target /left over ) - current run rate.
= (282/30)- 3.2.
= 6.2.
(2)
Shreya said:
5 years ago
In a cricket match, Ashwin scored 40perct. Of total run scored by his team & Arijit scored 140 run which is 200/9perct less than Ashwin's score, find total run scored by Ashwin's team, Anyone please answer it.
(3)
Suchi said:
5 years ago
Use the Average formula :
Average = sum of observations/number of observations.
For first 10 overs :
3.2 = Sum/10 --> Sum = 32--> Run in first 10 overs.
The total score is 282. First 10 overs, we scored 32 runs. So, remaining (282-32) runs=250 runs in 40 overs.
Applying the formula:
Average = sum of observations/number of observations.
Average= 250/40 = 6.25.
Average = sum of observations/number of observations.
For first 10 overs :
3.2 = Sum/10 --> Sum = 32--> Run in first 10 overs.
The total score is 282. First 10 overs, we scored 32 runs. So, remaining (282-32) runs=250 runs in 40 overs.
Applying the formula:
Average = sum of observations/number of observations.
Average= 250/40 = 6.25.
(14)
Masthan said:
5 years ago
10 * 3.2 = 32
40 * X = 282
=> 282 - 32 = 250.
40X = 250.
X = 250/40.
X = 6.25.
40 * X = 282
=> 282 - 32 = 250.
40X = 250.
X = 250/40.
X = 6.25.
(9)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers