Aptitude - Area - Discussion

@Amit kumar. How the edges are 7?

If that person walked along edges. Approximately, what was the percent wasted by walking along the edges?

Please give me the answer.

1.41*1.41x=2x

Let abcd be the square with each side of the square = 8m then

ab+bc=2 x 8= 16m
ac= sqrt(16)=4m

solving = 16-4= 12m

Hence, 4/12*100=33.33 approx.

You (Amit) choose the sides of a rectangle not SQUARE.

EXAMPLE METHOD.

According to Pythagoras FOR SQUARE the sides are 2 & 2 or diagonal 2*sqrt(2) = 2*1.141 = 2.828 {where sqrt(2) = 1.141}.

Edges are 2+2 then 4-2.828 = 1.172 (Difference).

(1.172/4)*100 = 29.3 = 30 approx.

Simple method:

Edge of square let be x.

Then diagonal of square will be 2 sqrt(x).

Edge distance - Diagonal distance (difference).

2x-2sqrt(x) = x (2-sqrt(2)) = (2-1.414)x = 0.586x.

%AGE.

(0.586x/2x)*100 = (0.586/2)*100 = 29.3 (30 approx).

From the fig shown above.
Root of AB square + BC square = AC.

I will go with @Ajay's method where he took side as 10 instead of variable.

Because is you take variable you go land up in confusion.

AC = Root of (2x).

Root of 2 = 1.41.

But what about root of x?

AC = root (2x).
Root of 2 = 1.41.

But where did the root of x disappeared?

How it came (.59x)m?

IN a sqare let us assume the sides be 3, 4 units then the diagonal will be 5 by pythagorus theorem ..thus 2 units are saved (7-5) .. total saved %=2/7*100 =28.57 i e 30%