Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 8)
8.
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
Answer: Option
Explanation:
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
| Saving % = |  |
0.59x | x 100 |  % |
= 30% (approx.) |
| 2x |
Discussion:
38 comments Page 1 of 4.
P.bharathi said:
1 decade ago
Saving on 2x metres = (0.59x) m.
How this step arise ? Please explain me clearly.
How this step arise ? Please explain me clearly.
Sneha G.B said:
1 decade ago
saving 2x meters means......
2x-1.41x=0.59x
2x-1.41x=0.59x
(1)
Ashu said:
1 decade ago
Use pyth. Theorem so you get the value of diagonal ac that is root 2 or 1. 41x. Now the distance saved by walking diagonally is 2x-1.41x i.e. 0.59x.
Sandeep said:
1 decade ago
Any other way to solve this problem ?
Kaps said:
1 decade ago
Easiest way told by ashu.
J.Gopikrishna said:
1 decade ago
Please tell easy way to solve the problem?
Suresh said:
1 decade ago
How Ac=root of2X?
Sumit said:
1 decade ago
1.41*1.41x=2x
KB3 said:
1 decade ago
Let abcd be the square with each side of the square = 8m then
ab+bc=2 x 8= 16m
ac= sqrt(16)=4m
solving = 16-4= 12m
Hence, 4/12*100=33.33 approx.
ab+bc=2 x 8= 16m
ac= sqrt(16)=4m
solving = 16-4= 12m
Hence, 4/12*100=33.33 approx.
Abhi said:
1 decade ago
IN a sqare let us assume the sides be 3, 4 units then the diagonal will be 5 by pythagorus theorem ..thus 2 units are saved (7-5) .. total saved %=2/7*100 =28.57 i e 30%
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