Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 8)
8.
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
Answer: Option
Explanation:
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = | ![]() |
0.59x | x 100 | ![]() |
= 30% (approx.) |
2x |
Discussion:
38 comments Page 1 of 4.
Fiza said:
2 years ago
If we go diagonal means a square cut in between gives a triangle
so a total 3 sides.
let's say 2 sides and 1 hypotenuse.
Let sides = x.
x + x = hypotenuse^2.
2x = hypotenuse^2.
This power 2 becomes root on the other side.
√ 2x is = hypotenuse.
√ 2x is 1.414x.
So now, in 2x we minus 1.414x gives us 0.59x // we do this because we calculate the total distance here.
The maximum distance was 2x but we traveled only 1.414x so 0.59 x distance was extra so we used that further.
The remaining distance/total distance to the percentage.
which is,
0.59X/2X * 100
= 30%.
Hope you got it.
so a total 3 sides.
let's say 2 sides and 1 hypotenuse.
Let sides = x.
x + x = hypotenuse^2.
2x = hypotenuse^2.
This power 2 becomes root on the other side.
√ 2x is = hypotenuse.
√ 2x is 1.414x.
So now, in 2x we minus 1.414x gives us 0.59x // we do this because we calculate the total distance here.
The maximum distance was 2x but we traveled only 1.414x so 0.59 x distance was extra so we used that further.
The remaining distance/total distance to the percentage.
which is,
0.59X/2X * 100
= 30%.
Hope you got it.
(10)
Mohammed Idris said:
4 years ago
@All.
Here is the solution.
Let side of squares be "5" on alll sides.
so area=5*5 = 25,
so: AB2 = 5*5 =25,
AD2 = 5*5 =25.
pythogorus: AC2 = AB2+BC2.
AC2 = 25+25.
AC = root(50).
AC = 7.07.
Now,
= AC/areax100.
= 7.07/25 x100 = 28.48~ 30 ans.
Here is the solution.
Let side of squares be "5" on alll sides.
so area=5*5 = 25,
so: AB2 = 5*5 =25,
AD2 = 5*5 =25.
pythogorus: AC2 = AB2+BC2.
AC2 = 25+25.
AC = root(50).
AC = 7.07.
Now,
= AC/areax100.
= 7.07/25 x100 = 28.48~ 30 ans.
(5)
Punni said:
5 years ago
@Riya.
Name the sqaure as ABCD. The person is moving from A to C (diagonally) instead of AB + BC (along the edges). As we can see the souce is point A and the destination is point C.
We actually need to find how much distance (edges) he saved by chosing to move from displacement (daigonally) aprt.
Name the sqaure as ABCD. The person is moving from A to C (diagonally) instead of AB + BC (along the edges). As we can see the souce is point A and the destination is point C.
We actually need to find how much distance (edges) he saved by chosing to move from displacement (daigonally) aprt.
(1)
Saipriya said:
5 years ago
Why do we take the percentage over 2x rather than 1.41x?
(2)
Riya said:
7 years ago
@All.
Along the edges, that means more than one side, so how come it has been decided that it is only 2 sides? Solution has been given only for 2 sides. Why?
Why it can't be 4 sides?
Along the edges, that means more than one side, so how come it has been decided that it is only 2 sides? Solution has been given only for 2 sides. Why?
Why it can't be 4 sides?
Prajakta said:
7 years ago
Savings on 2xmeters = (0.59x)meter how?
(4)
Rahul said:
8 years ago
let us assume the side of square is 10 cm.
In a square all sides are equal.
To find the diagonal of a square we can use the following formula= Squareroot of (2*(side^2)).
In this case= Square root of (2*(10^2)) = 14.142.
Distance Traveled=14.142.
Distance if used the edge of the square= 10*2= 20.
Saving=20-14.142=5.858.
Saving in %=5.858/20 =30%.
In a square all sides are equal.
To find the diagonal of a square we can use the following formula= Squareroot of (2*(side^2)).
In this case= Square root of (2*(10^2)) = 14.142.
Distance Traveled=14.142.
Distance if used the edge of the square= 10*2= 20.
Saving=20-14.142=5.858.
Saving in %=5.858/20 =30%.
(2)
Ramakanth said:
8 years ago
Please tell me an easy way to solve the problem with the clear explanation.
Senthil said:
8 years ago
@Amit kumar. How the edges are 7?
Navaneeth said:
9 years ago
If that person walked along edges. Approximately, what was the percent wasted by walking along the edges?
Please give me the answer.
Please give me the answer.
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