Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 8)
8.
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
Answer: Option
Explanation:
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = | ![]() |
0.59x | x 100 | ![]() |
= 30% (approx.) |
2x |
Discussion:
39 comments Page 1 of 4.
Fiza said:
2 years ago
If we go diagonal means a square cut in between gives a triangle
so a total 3 sides.
let's say 2 sides and 1 hypotenuse.
Let sides = x.
x + x = hypotenuse^2.
2x = hypotenuse^2.
This power 2 becomes root on the other side.
√ 2x is = hypotenuse.
√ 2x is 1.414x.
So now, in 2x we minus 1.414x gives us 0.59x // we do this because we calculate the total distance here.
The maximum distance was 2x but we traveled only 1.414x so 0.59 x distance was extra so we used that further.
The remaining distance/total distance to the percentage.
which is,
0.59X/2X * 100
= 30%.
Hope you got it.
so a total 3 sides.
let's say 2 sides and 1 hypotenuse.
Let sides = x.
x + x = hypotenuse^2.
2x = hypotenuse^2.
This power 2 becomes root on the other side.
√ 2x is = hypotenuse.
√ 2x is 1.414x.
So now, in 2x we minus 1.414x gives us 0.59x // we do this because we calculate the total distance here.
The maximum distance was 2x but we traveled only 1.414x so 0.59 x distance was extra so we used that further.
The remaining distance/total distance to the percentage.
which is,
0.59X/2X * 100
= 30%.
Hope you got it.
(10)
Faziha said:
9 years ago
We have to find saving distance from A to C.
First, from edges the distance we have to calculate.
So let's take side of a square as X
So for A to C.
We have to cross A to B then B to C.
So, X + X = 2X.
If we travel diagonally means the distance took is root of 2 multiplied by X.
So, saving will b 2X - root 2 X.
So (2.00 - 1.41) X = 0.59 X.
Saving % is 0.59X/2X * 100 = 30%.
First, from edges the distance we have to calculate.
So let's take side of a square as X
So for A to C.
We have to cross A to B then B to C.
So, X + X = 2X.
If we travel diagonally means the distance took is root of 2 multiplied by X.
So, saving will b 2X - root 2 X.
So (2.00 - 1.41) X = 0.59 X.
Saving % is 0.59X/2X * 100 = 30%.
(6)
Mohammed Idris said:
4 years ago
@All.
Here is the solution.
Let side of squares be "5" on alll sides.
so area=5*5 = 25,
so: AB2 = 5*5 =25,
AD2 = 5*5 =25.
pythogorus: AC2 = AB2+BC2.
AC2 = 25+25.
AC = root(50).
AC = 7.07.
Now,
= AC/areax100.
= 7.07/25 x100 = 28.48~ 30 ans.
Here is the solution.
Let side of squares be "5" on alll sides.
so area=5*5 = 25,
so: AB2 = 5*5 =25,
AD2 = 5*5 =25.
pythogorus: AC2 = AB2+BC2.
AC2 = 25+25.
AC = root(50).
AC = 7.07.
Now,
= AC/areax100.
= 7.07/25 x100 = 28.48~ 30 ans.
(5)
Prajakta said:
7 years ago
Savings on 2xmeters = (0.59x)meter how?
(4)
Maaz said:
1 decade ago
Simple go for the formulas of Area of Square. There are two formulas:
1) Area of Square = (Sides)2.
2) Area of Square = 1/2 (Diagonals)2.
Let 'S' is a side of square we know that all the sides of a square is equal. By first Formula Area will be S^2. Now putting this S^2 in 2nd Formula. We got the diagonal.
By second formula:
S^2 = 1/2(Diagonal)^2.
Taking square root on both sides.
Square root of 2*S = Diagonal.
Now we have to find Diagonal.
Diagonal = 1.414S(Square root of 2 = 1.414).
So The difference between Diagonal and Edges is:
2S-1.414S = 0.59S.
Percentage saved not by walk on edges = Extra Walk/Total Walk*100.
= 0.59S/2S*100 = 30%.
1) Area of Square = (Sides)2.
2) Area of Square = 1/2 (Diagonals)2.
Let 'S' is a side of square we know that all the sides of a square is equal. By first Formula Area will be S^2. Now putting this S^2 in 2nd Formula. We got the diagonal.
By second formula:
S^2 = 1/2(Diagonal)^2.
Taking square root on both sides.
Square root of 2*S = Diagonal.
Now we have to find Diagonal.
Diagonal = 1.414S(Square root of 2 = 1.414).
So The difference between Diagonal and Edges is:
2S-1.414S = 0.59S.
Percentage saved not by walk on edges = Extra Walk/Total Walk*100.
= 0.59S/2S*100 = 30%.
(2)
Saipriya said:
5 years ago
Why do we take the percentage over 2x rather than 1.41x?
(2)
Rahul said:
8 years ago
let us assume the side of square is 10 cm.
In a square all sides are equal.
To find the diagonal of a square we can use the following formula= Squareroot of (2*(side^2)).
In this case= Square root of (2*(10^2)) = 14.142.
Distance Traveled=14.142.
Distance if used the edge of the square= 10*2= 20.
Saving=20-14.142=5.858.
Saving in %=5.858/20 =30%.
In a square all sides are equal.
To find the diagonal of a square we can use the following formula= Squareroot of (2*(side^2)).
In this case= Square root of (2*(10^2)) = 14.142.
Distance Traveled=14.142.
Distance if used the edge of the square= 10*2= 20.
Saving=20-14.142=5.858.
Saving in %=5.858/20 =30%.
(2)
Sneha G.B said:
1 decade ago
saving 2x meters means......
2x-1.41x=0.59x
2x-1.41x=0.59x
(1)
Atul jain said:
1 decade ago
Let we have a square. starting from left top to right A,B,C,D.
After that make a diagonal AC.
As we know that we don't know the side of square then we assume x.
Now we start to run from A to C then path is AB+BC and its value,
is x+x = 2x.
Then equation is AB+BC = 2x.
Now the diagonal of the square formula is,
d = square root of 2 x.
d = 1.41x.
Saving per cent is ((2x-1.41x)/2x)*100 .
29.5. approx 30.
After that make a diagonal AC.
As we know that we don't know the side of square then we assume x.
Now we start to run from A to C then path is AB+BC and its value,
is x+x = 2x.
Then equation is AB+BC = 2x.
Now the diagonal of the square formula is,
d = square root of 2 x.
d = 1.41x.
Saving per cent is ((2x-1.41x)/2x)*100 .
29.5. approx 30.
(1)
Suresha E S said:
1 decade ago
AC = root (2x).
Root of 2 = 1.41.
But where did the root of x disappeared?
Root of 2 = 1.41.
But where did the root of x disappeared?
(1)
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