Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 8)
8.
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
Answer: Option
Explanation:
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = | ![]() |
0.59x | x 100 | ![]() |
= 30% (approx.) |
2x |
Discussion:
38 comments Page 1 of 4.
Fiza said:
2 years ago
If we go diagonal means a square cut in between gives a triangle
so a total 3 sides.
let's say 2 sides and 1 hypotenuse.
Let sides = x.
x + x = hypotenuse^2.
2x = hypotenuse^2.
This power 2 becomes root on the other side.
√ 2x is = hypotenuse.
√ 2x is 1.414x.
So now, in 2x we minus 1.414x gives us 0.59x // we do this because we calculate the total distance here.
The maximum distance was 2x but we traveled only 1.414x so 0.59 x distance was extra so we used that further.
The remaining distance/total distance to the percentage.
which is,
0.59X/2X * 100
= 30%.
Hope you got it.
so a total 3 sides.
let's say 2 sides and 1 hypotenuse.
Let sides = x.
x + x = hypotenuse^2.
2x = hypotenuse^2.
This power 2 becomes root on the other side.
√ 2x is = hypotenuse.
√ 2x is 1.414x.
So now, in 2x we minus 1.414x gives us 0.59x // we do this because we calculate the total distance here.
The maximum distance was 2x but we traveled only 1.414x so 0.59 x distance was extra so we used that further.
The remaining distance/total distance to the percentage.
which is,
0.59X/2X * 100
= 30%.
Hope you got it.
(10)
Faziha said:
9 years ago
We have to find saving distance from A to C.
First, from edges the distance we have to calculate.
So let's take side of a square as X
So for A to C.
We have to cross A to B then B to C.
So, X + X = 2X.
If we travel diagonally means the distance took is root of 2 multiplied by X.
So, saving will b 2X - root 2 X.
So (2.00 - 1.41) X = 0.59 X.
Saving % is 0.59X/2X * 100 = 30%.
First, from edges the distance we have to calculate.
So let's take side of a square as X
So for A to C.
We have to cross A to B then B to C.
So, X + X = 2X.
If we travel diagonally means the distance took is root of 2 multiplied by X.
So, saving will b 2X - root 2 X.
So (2.00 - 1.41) X = 0.59 X.
Saving % is 0.59X/2X * 100 = 30%.
(6)
Mohammed Idris said:
4 years ago
@All.
Here is the solution.
Let side of squares be "5" on alll sides.
so area=5*5 = 25,
so: AB2 = 5*5 =25,
AD2 = 5*5 =25.
pythogorus: AC2 = AB2+BC2.
AC2 = 25+25.
AC = root(50).
AC = 7.07.
Now,
= AC/areax100.
= 7.07/25 x100 = 28.48~ 30 ans.
Here is the solution.
Let side of squares be "5" on alll sides.
so area=5*5 = 25,
so: AB2 = 5*5 =25,
AD2 = 5*5 =25.
pythogorus: AC2 = AB2+BC2.
AC2 = 25+25.
AC = root(50).
AC = 7.07.
Now,
= AC/areax100.
= 7.07/25 x100 = 28.48~ 30 ans.
(5)
Prajakta said:
7 years ago
Savings on 2xmeters = (0.59x)meter how?
(4)
Saipriya said:
5 years ago
Why do we take the percentage over 2x rather than 1.41x?
(2)
Rahul said:
8 years ago
let us assume the side of square is 10 cm.
In a square all sides are equal.
To find the diagonal of a square we can use the following formula= Squareroot of (2*(side^2)).
In this case= Square root of (2*(10^2)) = 14.142.
Distance Traveled=14.142.
Distance if used the edge of the square= 10*2= 20.
Saving=20-14.142=5.858.
Saving in %=5.858/20 =30%.
In a square all sides are equal.
To find the diagonal of a square we can use the following formula= Squareroot of (2*(side^2)).
In this case= Square root of (2*(10^2)) = 14.142.
Distance Traveled=14.142.
Distance if used the edge of the square= 10*2= 20.
Saving=20-14.142=5.858.
Saving in %=5.858/20 =30%.
(2)
Maaz said:
1 decade ago
Simple go for the formulas of Area of Square. There are two formulas:
1) Area of Square = (Sides)2.
2) Area of Square = 1/2 (Diagonals)2.
Let 'S' is a side of square we know that all the sides of a square is equal. By first Formula Area will be S^2. Now putting this S^2 in 2nd Formula. We got the diagonal.
By second formula:
S^2 = 1/2(Diagonal)^2.
Taking square root on both sides.
Square root of 2*S = Diagonal.
Now we have to find Diagonal.
Diagonal = 1.414S(Square root of 2 = 1.414).
So The difference between Diagonal and Edges is:
2S-1.414S = 0.59S.
Percentage saved not by walk on edges = Extra Walk/Total Walk*100.
= 0.59S/2S*100 = 30%.
1) Area of Square = (Sides)2.
2) Area of Square = 1/2 (Diagonals)2.
Let 'S' is a side of square we know that all the sides of a square is equal. By first Formula Area will be S^2. Now putting this S^2 in 2nd Formula. We got the diagonal.
By second formula:
S^2 = 1/2(Diagonal)^2.
Taking square root on both sides.
Square root of 2*S = Diagonal.
Now we have to find Diagonal.
Diagonal = 1.414S(Square root of 2 = 1.414).
So The difference between Diagonal and Edges is:
2S-1.414S = 0.59S.
Percentage saved not by walk on edges = Extra Walk/Total Walk*100.
= 0.59S/2S*100 = 30%.
(2)
Sneha G.B said:
1 decade ago
saving 2x meters means......
2x-1.41x=0.59x
2x-1.41x=0.59x
(1)
Punni said:
5 years ago
@Riya.
Name the sqaure as ABCD. The person is moving from A to C (diagonally) instead of AB + BC (along the edges). As we can see the souce is point A and the destination is point C.
We actually need to find how much distance (edges) he saved by chosing to move from displacement (daigonally) aprt.
Name the sqaure as ABCD. The person is moving from A to C (diagonally) instead of AB + BC (along the edges). As we can see the souce is point A and the destination is point C.
We actually need to find how much distance (edges) he saved by chosing to move from displacement (daigonally) aprt.
(1)
Suresha E S said:
10 years ago
AC = root (2x).
Root of 2 = 1.41.
But where did the root of x disappeared?
Root of 2 = 1.41.
But where did the root of x disappeared?
(1)
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