Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 8)
8.
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
20
24
30
33
Answer: Option
Explanation:

Let the side of the square(ABCD) be x metres.

Then, AB + BC = 2x metres.

AC = 2x = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % = 0.59x x 100 % = 30% (approx.)
2x

Discussion:
38 comments Page 4 of 4.

Pragnya said:   1 decade ago
Please can anyone explain the last step in the solution? Which formula has been used there?

Anu said:   1 decade ago
What is that 1.41?

Lakshya said:   1 decade ago
Why should we have to multiply 0.59x/2x by 100? somebody please help me.

Suraj said:   1 decade ago
How the each side of square is 1m?

King cobra said:   1 decade ago
Hey KB3. You are wrong. Solve by PYTHOGORUS theorem,,

From the fig shown above.
Root of AB square + BC square = AC.

Sudhakar said:   1 decade ago
Suppose ab = 2, ac = 2 then ab+ac=4.

Diagonal bc = ?

Pythagoras Proof bc^2 = ac^2+ab^2 (here ^2 means square).
bc^2= 4+4.
bc=(square root of 8).
bc= 2.83.

Gain = 4-2.83 = 1.17.

Gain(%) = (1.17/4)*100 = 29.28%.

Arpit jain said:   1 decade ago
Hey kb3 u have used wrong formula
its (square root of 2)*(X)
ab+bc = 16m
sqrt(2)*8 = 11.313
16-11.313 = 4.68
(4.68*100)/16 = 29.28%

Ajay said:   1 decade ago
Lets say sides of square is 10 and let diagonal be x therefore by Pythagoras theorem.

X2 = (10) 2 + (10) 2 = 200.

X = 10root2 = 10 x 14.1 (root2 = 1.412).

Therefore 20 - 14.1 = 5.9.

5.9/20 = 0.30 i.e. approx 30%.


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