Aptitude - Area - Discussion

@Riya.

Name the sqaure as ABCD. The person is moving from A to C (diagonally) instead of AB + BC (along the edges). As we can see the souce is point A and the destination is point C.

We actually need to find how much distance (edges) he saved by chosing to move from displacement (daigonally) aprt.

Please tell me an easy way to solve the problem with the clear explanation.

@Amit kumar. How the edges are 7?

If that person walked along edges. Approximately, what was the percent wasted by walking along the edges?

Please give me the answer.

@All.

Along the edges, that means more than one side, so how come it has been decided that it is only 2 sides? Solution has been given only for 2 sides. Why?

Why it can't be 4 sides?

Saving on 2x metres = (0.59x) m.

How this step arise ? Please explain me clearly.

You (Amit) choose the sides of a rectangle not SQUARE.

EXAMPLE METHOD.

According to Pythagoras FOR SQUARE the sides are 2 & 2 or diagonal 2*sqrt(2) = 2*1.141 = 2.828 {where sqrt(2) = 1.141}.

Edges are 2+2 then 4-2.828 = 1.172 (Difference).

(1.172/4)*100 = 29.3 = 30 approx.

Simple method:

Edge of square let be x.

Then diagonal of square will be 2 sqrt(x).

Edge distance - Diagonal distance (difference).

2x-2sqrt(x) = x (2-sqrt(2)) = (2-1.414)x = 0.586x.

%AGE.

(0.586x/2x)*100 = (0.586/2)*100 = 29.3 (30 approx).

According to Pythagoras the side are 3&4 or diagonal 5.

Edges are 7 then 7-5=2 (Different).

(2/7)=(x/100).

Solve x=28.57142857 (i.e approximately 30).

I will go with @Ajay's method where he took side as 10 instead of variable.

Because is you take variable you go land up in confusion.

AC = Root of (2x).

Root of 2 = 1.41.

But what about root of x?

AC = root (2x).
Root of 2 = 1.41.

But where did the root of x disappeared?